Question 18 Certainly! Here is the transcribed text from the image as if it would appear on an educational website:---### Physics Problems involving Circular Motion18. **Carousel Ride:** - The horse on a carousel is 14.1 m from the central axis. If the carousel rotates at 0.1 rev/s, how long does it take the horse to go around twice? - How fast is a child on the horse going (in m/s)?19. **Earth's Orbit:** - The radius of the earth's very nearly circular orbit around the sun is \(1.50 \times 10^{11}\) m. Find the magnitude of the earth's velocity as it travels around the sun. Assume a year of 365 days. - Find the magnitude of the earth’s centripetal acceleration.20. **Wind Turbine Blades:** - Modern wind turbines are larger than they appear, and despite their apparently lazy motion, the speed of the blade's tips can be quite high; many times higher than the wind speed. A turbine has blades 54 m long that spin at 14 rpm. - At the tip of a blade, what is the speed? - At the tip of a blade, what is the centripetal acceleration?3. **Human Centrifuge:** - To withstand "g-forces" of up to 10g, caused by suddenly pulling out of a steep dive, fighter jet pilots train on a "human centrifuge." 10g is an acceleration of 98 m/s². - If the length of the centrifuge arm is 14 m, at what speed is the rider moving when she experiences 10g?--- These questions introduce students to practical applications of circular motion, involving scenarios ranging from amusement park rides to astronomical and technological contexts. Students can apply formulas for circular velocity and centripetal acceleration to find solutions.*Note: There are no graphs or diagrams included in the provided image.*

18 - Given: Radius, r=4.1 m The carousel rotates with angular velocity, ω=0.14 rev/s To determine: (a) Time taken by the horse to go around twice. (b) The linear speed of child on the horse going (in m/s).The angular velocity, ω=0.14 rev/s ω=0.14 rev/s =0.14×2π radians/s ω=0.8796 rad/s a) for 1 round ,the angular displacement is 2π radians and for 2 round angular displacement will be θ = 2(2π) = 12.5664 radians We know that θ=ωt t=θ/ω (1) Where t is time taken Putting θ = 12.5664 radians and ω=0.8796 rad/s in equation (1) t= (12.5664 rad)/(0.8796 rad/s) t = 14.29 s Time taken by the horse to go around twice is 14.29 s.(b) The linear speed of child on the horse going We know that v = rω in equation (2) Where v is linear speed , r is radius and ω is angular velocity. We have to determine v, Putting r=4.1 m and ω=0.8796 rad/s v = (4.1 m)(0.8796 rad/s) v = 3.606 m/s The linear speed of child on the horse going is 3.606 m/s

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Physics

W Hat Is a uISk S Inequency iH FeV/s? 18. The horse on a carousel is 4.1 m from the central axis. If the carousel rotates at 0.14 rev/s, how long does it take the horse to go around twice? How fast is a child on the horse going (in m/s)?

W Hat Is a uISk S Inequency iH FeV/s? 18. The horse on a carousel is 4.1 m from the central axis. If the carousel rotates at 0.14 rev/s, how long does it take the horse to go around twice? How fast is a child on the horse going (in m/s)?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

Question

Question 18

Certainly! Here is the transcribed text from the image as if it would appear on an educational website:

---

### Physics Problems involving Circular Motion

18. **Carousel Ride:**
- The horse on a carousel is 14.1 m from the central axis. If the carousel rotates at 0.1 rev/s, how long does it take the horse to go around twice?
- How fast is a child on the horse going (in m/s)?

19. **Earth's Orbit:**
- The radius of the earth's very nearly circular orbit around the sun is \(1.50 \times 10^{11}\) m. Find the magnitude of the earth's velocity as it travels around the sun. Assume a year of 365 days.
- Find the magnitude of the earth’s centripetal acceleration.

20. **Wind Turbine Blades:**
- Modern wind turbines are larger than they appear, and despite their apparently lazy motion, the speed of the blade's tips can be quite high; many times higher than the wind speed. A turbine has blades 54 m long that spin at 14 rpm.
- At the tip of a blade, what is the speed?
- At the tip of a blade, what is the centripetal acceleration?

3. **Human Centrifuge:**
- To withstand "g-forces" of up to 10g, caused by suddenly pulling out of a steep dive, fighter jet pilots train on a "human centrifuge." 10g is an acceleration of 98 m/s².
- If the length of the centrifuge arm is 14 m, at what speed is the rider moving when she experiences 10g?

---

These questions introduce students to practical applications of circular motion, involving scenarios ranging from amusement park rides to astronomical and technological contexts. Students can apply formulas for circular velocity and centripetal acceleration to find solutions.

*Note: There are no graphs or diagrams included in the provided image.*

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