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A 4.15-g bullet is moving horizontally with a velocity of +340 m/s, where the sign + indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1196 g, and its velocity is +0.644 m/s after the bullet passes through it. The mass of the second block is 1518 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision. +340m/s Block 1 (a) Before collision +0.644m/s mblock 1=1196 (b) After collision mblock 2=1518 mbullet =4.15% (a) Vblock2= Number (b) KE after/KEbefore = Number i Block 2 i block 2 Units Units

A 4.15-g bullet is moving horizontally with a velocity of +340 m/s, where the sign + indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1196 g, and its velocity is +0.644 m/s after the bullet passes through it. The mass of the second block is 1518 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision. +340m/s Block 1 (a) Before collision +0.644m/s mblock 1=1196 (b) After collision mblock 2=1518 mbullet =4.15% (a) Vblock2= Number (b) KE after/KEbefore = Number i Block 2 i block 2 Units Units

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem: Bullet and Block Collision** A 4.15-g bullet is moving horizontally with a velocity of +340 m/s, where the sign + indicates that it is moving to the right (see part (a) of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part (b). Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1196 g, and its velocity is +0.644 m/s after the bullet passes through it. The mass of the second block is 1518 g. (a) **What is the velocity of the second block after the bullet imbeds itself?** (b) **Find the ratio of the total kinetic energy after the collision to that before the collision.** **Diagram Explanation:** 1. **Before Collision (Diagram a):** - A bullet with a velocity of +340 m/s is approaching two stationary blocks (Block 1 and Block 2) on a frictionless surface. 2. **After Collision (Diagram b):** - Block 1 is moving with a velocity of +0.644 m/s. - Block 2 and the embedded bullet are moving together. The velocity needs to be determined. - Mass of Block 1: 1196 g - Mass of Block 2: 1518 g - Mass of Bullet: 4.15 g **Questions to Solve:** - (a) Calculate v_block2 = ____ Units - (b) Calculate KE_after/KE_before = ____ Units
Transcribed Image Text:**Problem: Bullet and Block Collision** A 4.15-g bullet is moving horizontally with a velocity of +340 m/s, where the sign + indicates that it is moving to the right (see part (a) of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part (b). Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1196 g, and its velocity is +0.644 m/s after the bullet passes through it. The mass of the second block is 1518 g. (a) **What is the velocity of the second block after the bullet imbeds itself?** (b) **Find the ratio of the total kinetic energy after the collision to that before the collision.** **Diagram Explanation:** 1. **Before Collision (Diagram a):** - A bullet with a velocity of +340 m/s is approaching two stationary blocks (Block 1 and Block 2) on a frictionless surface. 2. **After Collision (Diagram b):** - Block 1 is moving with a velocity of +0.644 m/s. - Block 2 and the embedded bullet are moving together. The velocity needs to be determined. - Mass of Block 1: 1196 g - Mass of Block 2: 1518 g - Mass of Bullet: 4.15 g **Questions to Solve:** - (a) Calculate v_block2 = ____ Units - (b) Calculate KE_after/KE_before = ____ Units
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