is more stable than 3 and 2 because ) is highest number of Covalent bond and it is natural So , is more stable than 3 , 2 . 3 ) is more stable than 6 and less stable than ou because ( 3 ) is less number of covalent bond and it is charged and it is no + charge in it . his lowest stable because - L covalent bond charged + charge in it ( unstable ) Qz which of thense is stable ;W CHe =CH- NH2(3) CHe - CH - N H2- I> 3>2is more stable than 3and 2 beGuse W is highest number of Covalent bondand it is natural So, ir more Stable than 3,2.3) is more stable than 2) and less stable than as because (3) is less number of covalent bondand it is charged and it is no + chalge in it .Qis lowest stable becuse-L Covalent bond- charged+ charge in it (unstable)

Given: CH2=CH-NH2 (1) -CH2-+CH-NH2 (2) -CH2-CH=+NH2 (3)

Answered: W CHz =CH- NH2 (3) CHe - CH - N H2 I)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Concept explainers

Question

is more stable than 3 and 2 because ) is highest number of Covalent bond and it is natural So , is more stable than 3 , 2 . 3 ) is more stable than 6 and less stable than ou because ( 3 ) is less number of covalent bond and it is charged and it is no + charge in it . his lowest stable because - L covalent bond charged + charge in it ( unstable )

Qz which of thense is stable ;
W CHe =CH- NH2
(3) CHe - CH - N H2
- I> 3>2
is more stable than 3and 2 beGuse W is highest number of Covalent bond
and it is natural So, ir more Stable than 3,2.
3) is more stable than 2) and less stable than as because (3) is less number of covalent bond
and it is charged and it is no + chalge in it .
Qis lowest stable becuse-L Covalent bond
- charged
+ charge in it (unstable)

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions