wA large nationwide survey recently showed an unemployment rate of 4% in Australia. Themayor of a local town wonders if this national result holds true for her town, so she planson taking a sample of her residents to see if the unemployment rate is significantlydifferent than 4% in her town. Let 7 represent the unemployment rate in her town. Hereare the hypotheses she'll use:Null Hypothesis: π == 0.04Alternative Hypothesis: 0.04Which type of Error has been committed in the following situation?●She concludes the town's unemployment rate is 4% when it actually is not.O Type I ErrorO Type II ErrorO No ErrorFormula sheet.docx

Answered: Image /qna-images/answer/6db514cc-aeb0-46cf-9e8d-de25d3209ebb.jpg

Answered: W A large nationwide survey recently…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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section 10.3 Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places. Step 3 of 3: Do we reject the null hypothesis? Is there sufficient or insufficient data?
You are conducting a multinomial hypothesis test (α= 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ObservedFrequency ExpectedFrequency A 17 B 22 C 11 D 13 E 17 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.)χ2= What are the degrees of freedom for this test?d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = Is the p-value less than αα? yes no This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to…
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Question 5 (10 marks) a. Write the null and alternative hypothesis for the following and determine if it is a two-tailed, a left-tailed or a right-tailed test. i. A researcher is studying the effects of radical exercise program on knee surgery patients. There is a good chance the therapy will improve recovery time, but there's also the possibility it will make it worse. Average recovery times for knee surgery patients is 8.2 weeks. ii. Alumni group of a private institution wants to test if the college student, on the average, take less than 4 years to graduate.
156% of studentss entering four-year colleges receive a degree within six years. Is this percent larger than for students who play intramural sports? 183 of the 286 students who played intramural sports received a degree within six years. What can be concluded at the level of significance of a = -0.10 a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: 7 v ||Select an answer V (please enter a decimal) H [?v||Select an answer v (Please enter a decimal) c. The test statistic 7v (please show your answer to 3 decimal places.) d. The p-value (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer vthe null hypothesis. g. Thus, the final conclusion is that ,
You are conducting a multinomial hypothesis test (αα = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ObservedFrequency ExpectedFrequency SquaredPearsonResidual A 6 B 9 C 25 D 11 E 12 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.)χ2= What are the degrees of freedom for this test?d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = It may be best to use the =CHIDIST() function in Excel to do this calculation.The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the…
The average time in years to get an undergraduate degree in statistics was compared for meals and females. Random sample of 200 male statistics majors and 200 female statistics majors were taken. Choose the appropriate parameter(s) for this situation. [Hint: The parameter(s) to be used in your hypothesis]. O A. P1-P2 O B. H1-H2 O C. None of these O D. p O E. u
Suppose are running a study/poll about the proportion of voters who prefer Candidate A. You randomly sample 102 people and find that 70 of them match the condition you are testing.Suppose you are have the following null and alternative hypotheses for a test you are running:H0:p=0.68Ha:p<0.68Calculate the test statistic, rounded to 3 decimal places z=
A sheriff's department claims that it pays its male and female employees equal wages. You analyze the wages they actually paid the deputies, and you find that the average hourly wage for males was $13.50 and for females it was $12.30. You conduct a t-test for this difference and get a t(obtained) of 1.31. (Hint: you will be using the two-sample hypothesis test) a. State the appropriate null and research hypotheses. b. If you had an alpha of .05 (one-tailed) with 60 degrees of freedom, what would be your t(critical)? c. Pretend you have a t(critical) of +2.000. Pretend you also calculated a t(obtained) of +1.31, write out a full interpretation based on the problem description above.
CHALLENGE ACTIVITY 402562.2600368.qx3zqy7 8.2.3: Hypothesis testing for two population proportions (one-tailed z-test). Jump to level 1 A university department chair believes that the afternoon section of a large survey class has a consistently lower proportion of students that pass the class compared to the morning section. The chair checks a random sample of student records from each section. The results of the data collected are shown below. Morning section Afternoon section Successes Observations p-hat_1 346 Successes 400 Observations 0.865 p-hat_2 Confidence level 95% -0.5548 p-value 0.2912 3 2 6 2 P= Ex 1.234 Morning section samples: ₁ Ex: 9 Afternoon section samples: 1₂ Sample proportion for morning section samples: p1 Sample proportion for afternoon section samples: p₂ – O 500 LE E 2 № 7 || ||| Ex: 1.234 D D DO
If, in a sample of n=16 selected from a normal population, X=58 and S=12, how many degrees of freedom does the t test have if you are testing the null hypothesis H0: μ=50? Question content area bottom Part 1 The degrees of freedom are enter your response here.
A decade-old study found that the proportion of high school seniors who felt that "getting rich" was an important personal goal was 68%. Suppose that we have reason to believe that this proportion has changed, and we wish to carry out a hypothesis test to see if our belief can be supported. State the null hypothesis H, and the alternative hypothesis H that we would use for this test. H: 0 O

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