wA large nationwide survey recently showed an unemployment rate of 4% in Australia. Themayor of a local town wonders if this national result holds true for her town, so she planson taking a sample of her residents to see if the unemployment rate is significantlydifferent than 4% in her town. Let 7 represent the unemployment rate in her town. Hereare the hypotheses she'll use:Null Hypothesis: π == 0.04Alternative Hypothesis: 0.04Which type of Error has been committed in the following situation?●She concludes the town's unemployment rate is 4% when it actually is not.O Type I ErrorO Type II ErrorO No ErrorFormula sheet.docx

Answered: Image /qna-images/answer/6db514cc-aeb0-46cf-9e8d-de25d3209ebb.jpg

Answered: W A large nationwide survey recently…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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section 10.3 Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places. Step 3 of 3: Do we reject the null hypothesis? Is there sufficient or insufficient data?
You are conducting a multinomial hypothesis test (α= 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ObservedFrequency ExpectedFrequency A 17 B 22 C 11 D 13 E 17 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.)χ2= What are the degrees of freedom for this test?d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = Is the p-value less than αα? yes no This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to…
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You are conducting a multinomial hypothesis test (αα = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category ObservedFrequency ExpectedFrequency SquaredPearsonResidual A 6 B 9 C 25 D 11 E 12 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations.What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.)χ2= What are the degrees of freedom for this test?d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = It may be best to use the =CHIDIST() function in Excel to do this calculation.The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null accept the alternative As such, the…
Suppose are running a study/poll about the proportion of voters who prefer Candidate A. You randomly sample 102 people and find that 70 of them match the condition you are testing.Suppose you are have the following null and alternative hypotheses for a test you are running:H0:p=0.68Ha:p<0.68Calculate the test statistic, rounded to 3 decimal places z=
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A December 2017 Gallup Poll reported that 43% of Americans use the internet for an hour or more each day. You suspect that a greater proportion of students at your school use the internet that much. You take a random sample of 60 students and find that 36 of them use the internet for an hour or more each day. Assume your school has more than 600 students. You will test the hypotheses H, : p = 0.43, H,:p>0.43 , where p= the true proportion of students at your school who use the internet for an hour or more each day. Which of the following gives the correct test statistic for this test? 0.43 - 0.6 Z = (0.6)(0.4) 60 0.43-0.6 (0.6)(0.4) 600 0.6-0.43 (0.6)(0.4) 60 0.6 - 0.43 (0.43)(0.57) 60 36 - 60 (36)(24) 60
In a lightbulb factory, an administrator selects a random sample of bulbs produced on assembly line A and a random sample of bulbs produced on assembly line B. The administrator calculates the proportion of malfunctioning bulbs produced by each assembly line and finds that the difference between them (A - B) is 0.008. A researcher conducted a hypothesis test with the following hypotheses: H0: The proportion of malfunctioning bulbs from assembly line A is the sample as the proportion of malfunctioning bulbs from assembly line B. HA: The proportion of malfunctioning bulbs from assembly line A is greater than the proportion of malfunctioning bulbs from assembly line B. She found a P-value of 0.016. What is the best interpretation of this P-value? a If there is no difference in the proportions of all defective parts made on the two assembly lines, the probability of observing a difference of at least 0.008 is 0.016. b If there is a difference of 0.016 in the proportions…

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