vy(t) = voe 22 where vo =0.49 km/s, to = 390 s, and o = 65 s. Part F For this trajectory, what would the vertical component of acceleration for the module be at time tm = to -o = 325 s? Recall that acceleration is the derivative of velocity with respect to time.

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For this trajectory, what would the vertical component of acceleration for the module be? Having trouble figuring it out.

An engineer is considering possible trajectories to use for emergency descent of a lunar module from low moon orbit to the lunar surface and decides to investigate one for which the vertical component of velocity as a function of time is described by
(t-to)2
2,2 where vo = 0.49 km/s, to = 390 s, and o = 65 s.
Vy(t) = voe
Part F
For this trajectory, what would the vertical component of acceleration for the module be at time tm = to - o = 325 s? Recall that acceleration is the derivative of velocity with respect to time.
Transcribed Image Text:An engineer is considering possible trajectories to use for emergency descent of a lunar module from low moon orbit to the lunar surface and decides to investigate one for which the vertical component of velocity as a function of time is described by (t-to)2 2,2 where vo = 0.49 km/s, to = 390 s, and o = 65 s. Vy(t) = voe Part F For this trajectory, what would the vertical component of acceleration for the module be at time tm = to - o = 325 s? Recall that acceleration is the derivative of velocity with respect to time.
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