v¡(t) CCT1 R₁ R₁ = CCT2 Li ooooo L2 5 L₁ R2 R Rf 1 OA1 + + OA2 R ip#, Up# in#, Vn# Ra Rd CCT3 OA3 Ro Love OA# Ro Vo# vo(t) S s² + 25wns +w2²/12 For CCT2, prove that the 2nd order high pass filter can be written as: damping ratio 5 natural frequency = Wn Derived expressions for K, the damping ratio, and natural frequency in terms of CCT parameters (L1, L2, R1, R2, R). T₂(s) = K-

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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v¡(t) o
CCT1
R₁
! R₁
CCT2
Li
00000
00000
L2
L₁
00000
R₂
R
Rf
OA1
+
OA2
R
ip#, Vp#
in#, Vn#
Ra
Ra
CCT3
OA3
+
Ro
OA#
Ro
W
Vo#
o vo(t)
T₂(8) = K
S
s² + 2(wns + w2²/12
For CCT2, prove that the 2nd order high pass filter can be written as:
damping ratio = C
natural frequency = Wn
Derived expressions for K, the damping ratio, and natural frequency in terms of CCT parameters (L1,
L2, R1, R2, R).
Transcribed Image Text:v¡(t) o CCT1 R₁ ! R₁ CCT2 Li 00000 00000 L2 L₁ 00000 R₂ R Rf OA1 + OA2 R ip#, Vp# in#, Vn# Ra Ra CCT3 OA3 + Ro OA# Ro W Vo# o vo(t) T₂(8) = K S s² + 2(wns + w2²/12 For CCT2, prove that the 2nd order high pass filter can be written as: damping ratio = C natural frequency = Wn Derived expressions for K, the damping ratio, and natural frequency in terms of CCT parameters (L1, L2, R1, R2, R).
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