vi(t) CCT1 R₁ R₁ CCT2 Li voooo = ooooo 0000 L2 R₂ Rf OA1 + OA2 R 1 I Rd Ra ip#, Vp#. in#, Vn# CCT3 OA3 Ro + OA# Ro Vo# %(t) 82 s² + 25wns+w²/12 For CCT2, prove that the 2nd order high pass filter can be written as: damping ratio 5 natural frequency = Wn Derived expressions for K, the damping ratio, and natural frequency in terms of CCT parameters (L1, L2, R1, R2, R). T₂(s) = K-

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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vi(t)
CCT1
R₁
R₁
CCT2
Li
00000
=
00000
L₁
wwwww
L2 R₂
R
Rf
OA1
+
OA2
R
ip#, Vp#
in#, Vn#
Ra
Ra
CCT3
OA3
+
Ro
OA#
Vo#
Ro
wwo vo(t)
I
For CCT2, prove that the 2nd order high pass filter can be written as:
damping ratio (
natural frequency = Wn
Derived expressions for K, the damping ratio, and natural frequency in terms of CCT parameters (L1,
L2, R1, R2, R).
82
T₂(s) = K
s² + 25wns +w2/12
Transcribed Image Text:vi(t) CCT1 R₁ R₁ CCT2 Li 00000 = 00000 L₁ wwwww L2 R₂ R Rf OA1 + OA2 R ip#, Vp# in#, Vn# Ra Ra CCT3 OA3 + Ro OA# Vo# Ro wwo vo(t) I For CCT2, prove that the 2nd order high pass filter can be written as: damping ratio ( natural frequency = Wn Derived expressions for K, the damping ratio, and natural frequency in terms of CCT parameters (L1, L2, R1, R2, R). 82 T₂(s) = K s² + 25wns +w2/12
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