VRAAG 5 Die grafieke van f(x) = 1½ cosx en g(x)=sin(x +30°), vir die interval xe (0°; 180°). 2 is hieronder geskets. A(130,9°; 0,33) is die benaderde snypunt van die twee grafieke. A(130,9°; 0,33) 0º 90° 150° I 180° 5.1. 5.2 5.1 5.1 Skryf die periode van g neer. (1) 5.2 Skryf die amplitude van neer. e (1) 5 5.3 Bepaal die waarde van (180°) - g(180°) (L) 5.4 Gebruik die grafieke om die waardes van x in die interval re [0°; 180°] te bepaal, waarvoor: 5.4.1 f(x-10°) = g(x -10°) (1) 5.4.2 √√3 sin x + cos x ≥1 (4) [8]

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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VRAAG 5
Die grafieke van f(x) = 1½ cosx en g(x)=sin(x +30°), vir die interval xe (0°; 180°).
2
is hieronder geskets. A(130,9°; 0,33) is die benaderde snypunt van die twee grafieke.
A(130,9°; 0,33)
0º
90°
150°
I
180°
5.1.
5.2
5.1
5.1
Skryf die periode van g neer.
(1)
5.2
Skryf die amplitude van neer.
e
(1) 5
5.3
Bepaal die waarde van (180°) - g(180°)
(L)
5.4
Gebruik die grafieke om die waardes van x in die interval re [0°; 180°] te bepaal,
waarvoor:
5.4.1
f(x-10°) = g(x -10°)
(1)
5.4.2
√√3 sin x + cos x ≥1
(4)
[8]
Transcribed Image Text:VRAAG 5 Die grafieke van f(x) = 1½ cosx en g(x)=sin(x +30°), vir die interval xe (0°; 180°). 2 is hieronder geskets. A(130,9°; 0,33) is die benaderde snypunt van die twee grafieke. A(130,9°; 0,33) 0º 90° 150° I 180° 5.1. 5.2 5.1 5.1 Skryf die periode van g neer. (1) 5.2 Skryf die amplitude van neer. e (1) 5 5.3 Bepaal die waarde van (180°) - g(180°) (L) 5.4 Gebruik die grafieke om die waardes van x in die interval re [0°; 180°] te bepaal, waarvoor: 5.4.1 f(x-10°) = g(x -10°) (1) 5.4.2 √√3 sin x + cos x ≥1 (4) [8]
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