Find an equation of the tangent to the curve (in cartesian coordinates) at the point corresponding to the given value of the parameter. x = cose + sin 20 +2, y = sine + cos20 +2,0 = π 01-1 || y: x=¾+²/ y=2+2 None of these

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Find an equation of the tangent to the curve (in cartesian coordinates) at the point corresponding
to the given value of the parameter.
x = cose + sin 20+2, y = sin0+ cos20 +2,0 = π
O
-=-=-=-1
2
v = 7²/4
X
y= 22 +2²2/2
y=2+2
None of these
Transcribed Image Text:Find an equation of the tangent to the curve (in cartesian coordinates) at the point corresponding to the given value of the parameter. x = cose + sin 20+2, y = sin0+ cos20 +2,0 = π O -=-=-=-1 2 v = 7²/4 X y= 22 +2²2/2 y=2+2 None of these
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