nd an equation of the tangent line to the curve at each given point. x = 2 - 3 cos 0, y = 3 + 2 sin 0 y = -1 (-1, 3) (2,5) (4+3√3,2) y=5 y = 0 X X
nd an equation of the tangent line to the curve at each given point. x = 2 - 3 cos 0, y = 3 + 2 sin 0 y = -1 (-1, 3) (2,5) (4+3√3,2) y=5 y = 0 X X
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Transcribed Image Text:Find an equation of the tangent line to the curve at each given point.
x = 2 3 cos 0,
y = 3 + 2 sin 8
at (-1, 3)
at (2,5)
at (4+ 3√/3, 2)
2
y = 5
y = 0
-1
X
X
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Step 1: Find the equation of tangent line at the given points of the given curve
VIEWStep 2: Calculation of to determine the equation of tangent line at (-1,3)
VIEWStep 3: Calculation of to determine the equation of tangent line at (2,5)
VIEWStep 4: Calculation of to determine the equation of tangent line at ((4+3√3)/2,2)
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