Line impedanceMiM1TransformerVsVTM3M2Line impedanceпеutralLine impedanceM3Figure 2: Distribution lines equivalent circuit.Figure 1: Low voltage lines exiting the distributiontransformer center.In the given circuit, low voltage lines are seen coming out of a distribution transformerwhose Low Voltage side is star connected. R (QR = 0) phase for M1 line, S (@S = 120)phase for M2 line andT (oT = -120) phase is used for M3 line. The impedances of theloads at the end of the lines are (100 + j25) N and the impedances of the lines (1 + j) N.• Find the capacitor power required for compensation to be made at cos p= 0.984 (p = 10) at the end of the line.• Find line currents after compensation

Given data: Zm=100+j25 ΩZL=1+j ΩVph=230 Vϕ=10o

VR Line impedance Mi M1 Transformer Vs VT M3, M: M2 Line impedance neutral Line impedance M3 Figure 2: Distribution lines equivalent circuit. Figure 1: Low voltage lines exiting the distribution transformer center. In the given circuit, low voltage lines are seen coming out of a distribution transformer whose Low Voltage side is star connected. R (@R = 0) phase for M1 line, S (µS = 120) phase for M2 line andT (øT = -120) phase is used for M3 line. The impedances of the loads at the end ofthe lines are (100 + j25) N and the impedances of the lines (1 + j) N. • Find the capacitor power required for compensation to be made at cos 4= 0.984 (4 = 10) at the end of the line. • Find line currents after compensation

VR Line impedance Mi M1 Transformer Vs VT M3, M: M2 Line impedance neutral Line impedance M3 Figure 2: Distribution lines equivalent circuit. Figure 1: Low voltage lines exiting the distribution transformer center. In the given circuit, low voltage lines are seen coming out of a distribution transformer whose Low Voltage side is star connected. R (@R = 0) phase for M1 line, S (µS = 120) phase for M2 line andT (øT = -120) phase is used for M3 line. The impedances of the loads at the end ofthe lines are (100 + j25) N and the impedances of the lines (1 + j) N. • Find the capacitor power required for compensation to be made at cos 4= 0.984 (4 = 10) at the end of the line. • Find line currents after compensation

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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