For a 50 kVa distribution transformer, which on its high voltage side is 2400 V and on the short-circuit low voltage secondary has a voltage of 240 V with a frequency of 60 Hz, it has a leakage impedance of 0.72+j0.92 Ω on the high voltage side and 0.0070+j0.0090 Ω on the high voltage side low tension. The short-circuit test presented values of 48 V, 20.8 A and 617 W for high voltage. The impedance responsible for the excitation current is 6.32+j43.7 Ω referring to the low voltage side. One open circuit test, with the low voltage side energized, presented the values of 240 V, 5.14 A and 186W. According to the information presented, determine: a. Draw the equivalent circuit on the high voltage side and present the impedance values in the circuit. b.Draw the equivalent circuit on the low voltage side and present the impedance values in the circuit. c. For the high voltage value, calculate the value of the current flowing in the magnetizing impedance.
For a 50 kVa distribution transformer, which on its high voltage side is 2400 V and on the short-circuit low voltage secondary has a voltage of 240 V with a frequency of 60 Hz, it has a leakage impedance of 0.72+j0.92 Ω on the high voltage side and 0.0070+j0.0090 Ω on the high voltage side low tension. The short-circuit test presented values of 48 V, 20.8 A and 617 W for high voltage. The impedance responsible for the excitation current is 6.32+j43.7 Ω referring to the low voltage side. One open circuit test, with the low voltage side energized, presented the values of 240 V, 5.14 A and 186W. According to the information presented, determine:
a. Draw the equivalent circuit on the high voltage side and present the impedance values in the circuit.
b.Draw the equivalent circuit on the low voltage side and present the impedance values in the circuit.
c. For the high voltage value, calculate the value of the current flowing in the magnetizing impedance.
d.Determine the yield for an inductive 0.80 power factor. And determine the setting value of voltage at full load.
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