RVRFigure 20-2In the accompanying figure, let R = 20 W, Xc = 15 W, E = 12Đ0° V, and I = 2Đ0° A.Use the superposition theorem to determine VR and Vc.VR = 25.9Đ-31.4° V, Vc = 31.2Đ0° VVR = 2Đ131° V, Vc = 4.6Đ90° VVR = 25.9Đ148.6° V, Vc = 31.2Đ180° VVR = 47Đ-31.4° V, Vc = 22.7Đ90° V

Write the given values again as below. R=20 ΩXC=-j15 ΩE=12∠0° VI=2∠0° A

VR E Figure 20-2 In the accompanying figure, let R = 20 W, Xc = 15 W, E = 12Đ0° V, and I = 2Đ0° A. Use the superposition theorem to determine VR and Vc. O VR = 25.9Đ-31.4° V, Vc = 31.2Đ0° V O VR = 2Đ131° V, Vc = 4.6Đ90° V O VR = 25.9Đ148.6° V, Vc = 31.2Đ180° V O VR = 47Đ-31.4° V, Vc = 22.7Đ90° V

VR E Figure 20-2 In the accompanying figure, let R = 20 W, Xc = 15 W, E = 12Đ0° V, and I = 2Đ0° A. Use the superposition theorem to determine VR and Vc. O VR = 25.9Đ-31.4° V, Vc = 31.2Đ0° V O VR = 2Đ131° V, Vc = 4.6Đ90° V O VR = 25.9Đ148.6° V, Vc = 31.2Đ180° V O VR = 47Đ-31.4° V, Vc = 22.7Đ90° V

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

R
VR
Figure 20-2
In the accompanying figure, let R = 20 W, Xc = 15 W, E = 12Đ0° V, and I = 2Đ0° A.
Use the superposition theorem to determine VR and Vc.
VR = 25.9Đ-31.4° V, Vc = 31.2Đ0° V
VR = 2Đ131° V, Vc = 4.6Đ90° V
VR = 25.9Đ148.6° V, Vc = 31.2Đ180° V
VR = 47Đ-31.4° V, Vc = 22.7Đ90° V

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