• VP3. An object of mass m, hangs from a string that passes over a very light fixed pulley P1 as shown in the figure below. The string connects to a second very light pulley P2. A second string passes around this pulley with one end attached to a wall and the other to an object of mass m2 on a frictionless, horizontal table. (a) If a1 and a2 are the accelerations of m, and m2, respectively, what is the relation
• VP3. An object of mass m, hangs from a string that passes over a very light fixed pulley P1 as shown in the figure below. The string connects to a second very light pulley P2. A second string passes around this pulley with one end attached to a wall and the other to an object of mass m2 on a frictionless, horizontal table. (a) If a1 and a2 are the accelerations of m, and m2, respectively, what is the relation
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Ch6 VP3
![### Pulley System Problem - VP3
**Problem Statement:**
An object of mass \( m_1 \) hangs from a string that passes over a very light, fixed pulley \( P_1 \), as illustrated in the figure. The string connects to a second, very light pulley \( P_2 \). A second string passes around this pulley. One end is attached to a wall, and the other to an object of mass \( m_2 \) on a frictionless, horizontal table.
**Questions:**
(a) If \( a_1 \) and \( a_2 \) are the accelerations of \( m_1 \) and \( m_2 \) respectively, what is the relation between these accelerations?
(b) Find expressions for the tensions in the strings.
(c) Find the accelerations \( a_1 \) and \( a_2 \) in terms of the masses \( m_1 \) and \( m_2 \), and \( g \) (acceleration due to gravity).
**Diagram Explanation:**
- **\( P_1 \):** The fixed pulley over which the string with mass \( m_1 \) passes. This pulley changes the direction of the tension force in the string.
- **\( P_2 \):** The second pulley with a string passing over it. One end is attached to a wall, while the other end is connected to mass \( m_2 \), which sits on a frictionless horizontal table.
- **Mass \( m_1 \):** Hangs vertically, causing a downward force due to gravity.
- **Mass \( m_2 \):** Positioned on a horizontal table, experiencing horizontal motion due to the tension in the string connected through \( P_2 \).
These masses are connected in a system where their motions are interdependent due to the pulley arrangement, and solving for their accelerations and tensions involves applying Newton's Laws to the system.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9682b814-e7b6-40bb-8ab1-65efb8b73f6f%2F9e09afc9-2b12-46a6-b806-1a307da9f54c%2F246lztr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Pulley System Problem - VP3
**Problem Statement:**
An object of mass \( m_1 \) hangs from a string that passes over a very light, fixed pulley \( P_1 \), as illustrated in the figure. The string connects to a second, very light pulley \( P_2 \). A second string passes around this pulley. One end is attached to a wall, and the other to an object of mass \( m_2 \) on a frictionless, horizontal table.
**Questions:**
(a) If \( a_1 \) and \( a_2 \) are the accelerations of \( m_1 \) and \( m_2 \) respectively, what is the relation between these accelerations?
(b) Find expressions for the tensions in the strings.
(c) Find the accelerations \( a_1 \) and \( a_2 \) in terms of the masses \( m_1 \) and \( m_2 \), and \( g \) (acceleration due to gravity).
**Diagram Explanation:**
- **\( P_1 \):** The fixed pulley over which the string with mass \( m_1 \) passes. This pulley changes the direction of the tension force in the string.
- **\( P_2 \):** The second pulley with a string passing over it. One end is attached to a wall, while the other end is connected to mass \( m_2 \), which sits on a frictionless horizontal table.
- **Mass \( m_1 \):** Hangs vertically, causing a downward force due to gravity.
- **Mass \( m_2 \):** Positioned on a horizontal table, experiencing horizontal motion due to the tension in the string connected through \( P_2 \).
These masses are connected in a system where their motions are interdependent due to the pulley arrangement, and solving for their accelerations and tensions involves applying Newton's Laws to the system.
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