void ffx() is a function with no argument
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- function name- def my-polyStack using C++ programmijng language please Write a program to input an arithmetic expression, then 1. Match nested brackets found the expression, if they are matched correctly proceed to step 2.2. Evaluate the expression. Please not that the operands of the expression may contain more than one digit. just 3 function : 1.function to check the brackets 2.function from infix to postfix 3.function to evaluate the expression this is the cin of the arithmetic expression is : ((5+(6/2*3)-2)+1)= you can use this function also ::: struct node { int data; node *next; node(int d,node *n=0) { data=d; next=n; } }; class stack { node *topp; public: stack(); void push(int el); bool pop(); int top(); bool top(int &el); //~stack(); //void operator=(stack &o); //stack(stack &o); }; stack::stack() { topp=0; } void stack::push(int el) { topp=new node(el,topp); } bool stack::pop() { if(topp==0) return false; node *t=topp; topp=topp->next; delete t; return true; } int stack::top() {…Stack using C++ programmijng language please Write a program to input an arithmetic expression, then 1. Match nested brackets found the expression, if they are matched correctly proceed to step 2. 2. Evaluate the expression. Please not that the operands of the expression may contain more than one digit. just 3 function : 1.function to check the brackets 2.function from infix to postfix 3.function to evaluate the expression this is the cin of the arithmetic expression we will use : ((5+(6/2*3)-2)+1)= this will give you 13 and will go to next stage (5+(6/2*3)-2)+1)= this will give you missing open bracket ((5+(6/2*3)-2)+1= this will give you missing close bracket
- pointers as Arguments:In the C programming language there is no pass-by-reference syntax to passa variable by reference to a function. Instead a variable is passed by pointer(just to be confusing, sometimes passing by pointer is referred to as pass byreference). This Practice Program asks you to do the same thing as C.Here is the header for a function that takes as input a pointer to an integer:1. void addOne (int ∗ptrNum )Complete the function so it adds one to the integer referenced by ptrNum.Write a main function where an integer variable is defined, give it an initialvalue, call addOne, and output the variable. It should be incremented by 1.JAVA LANGUAGE CODE Postfix Calculator by CodeChum Admin One good implementation of computing infix expressions is to transform them to postfix and then evaluate via the postfix expression. Infix expressions is the common way of writing arithmetic expressions. The binary operator come between them as shown below: 2 * 5 + 9 - 10 / 20 In postfix expressions, the operands come first before the operator: 2 5 * 9 + 10 20 / - A stack can be used to evaluate postfix expressions. The operands are pushed onto the Stack and when an operator is found two operands are popped and the operation is performed and finally the result is pushed back onto the Stack. The final answer will be the lone element of the Stack. Input The first line contains a positive integer n representing the number of postfix expressions. What follows are n postfix expressions themselves. 5 10 20 + 30 15 2 * + 100 20 30 + / 90 20 10 + + 0 / 9 3 - 10 + 2 * Output A single line containing the result of…C++ Please put function after int main
- Stack using C++ programmijng language please Write a program to input an arithmetic expression, then 1. Match nested brackets found the expression, if they are matched correctly proceed to step 2.2. Evaluate the expression. Please not that the operands of the expression may contain more than one digit. the cin of the arithmetic expression is :: ((5+(6/2*3)-2)+1)= you can use this function also ::: struct node { int data; node *next; node(int d,node *n=0) { data=d; next=n; } }; class stack { node *topp; public: stack(); void push(int el); bool pop(); int top(); bool top(int &el); //~stack(); //void operator=(stack &o); //stack(stack &o); }; stack::stack() { topp=0; } void stack::push(int el) { topp=new node(el,topp); } bool stack::pop() { if(topp==0) return false; node *t=topp; topp=topp->next; delete t; return true; } int stack::top() { if(topp!=0) return topp->data; } bool stack::top(int &el) { if(topp==0) return false; el=topp->data; return true; }c++ programing Sample Testcase 0: Input: (-2) Output: Negative input Sample Testcase 1: Input: 0 Output: Zero size matrix Sample Testcase 2: Input 3 2 Output: Wrong entry Sample Testcase 3: Input 3 0 1 2 3 4 5 6 7 8 9 Output: 11 Sample Testcase 4: Input 3 1 1 2 3 4 5 6 7 8 9 Output: 19 #include <iostream> #include <cmath> using namespace std; int main() { int s, region; cin>>s>>region; int MAT[s][s]; //Start your code Here return 0; } MULTIPLE FUNCTIONS AND RECURSIVE FUNCTIONS Use C language