Vm v(t) = 1 (~ -Vm + Vz R Iz Z Figure 3.0a: R-L circuit with sinusoidal AC source + L to CH-1 v(t) = |" (~ Vm Vz(t) to CH-2 + -Vm R Iz(t) VR(t) Figure 3.0b: R-L circuit with sinusoidal AC source and measurement connections.

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For the circuit in Figure 3.0a: If v(t) = 10cos(⍵t + 0º) volts, R = 510 , and L = 4.7  mH; use your derived expressions to determine the magnitude ǁZǁ; the phase-angle,  ƟZo and the magnitude, ǁIZǁ at each frequency, f listed in below Table 3.0.  

Recall: ⍵ = 2πf; and 1kHz = 103Hz = 1000Hz. 

frequency, f (kHz) 

magnitude, ǁIZǁ 

(mA)

magnitude, ǁZǁ  (kΩ)

phase-angle, ƟZo (degrees)

0.1

     

0.5

     

1.0

     

5.0

     

10.0

     

50.0

     

200.0 

     
Vm
v(t) = 1 (~
-Vm
+
Vz
R
Iz
Z
Figure 3.0a: R-L circuit with sinusoidal AC source
+
L
to CH-1
v(t) = |" (~
Vm
Vz(t)
to CH-2
+
-Vm
R
Iz(t)
VR(t)
Figure 3.0b: R-L circuit with sinusoidal AC source and measurement connections.
Transcribed Image Text:Vm v(t) = 1 (~ -Vm + Vz R Iz Z Figure 3.0a: R-L circuit with sinusoidal AC source + L to CH-1 v(t) = |" (~ Vm Vz(t) to CH-2 + -Vm R Iz(t) VR(t) Figure 3.0b: R-L circuit with sinusoidal AC source and measurement connections.
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