IBI₁ = 1 AZ0°V₂Y₁Y₁ = 0.5 SY₂ = -j 0.5 SY3 = +j 0.25 SFIGURE 19-22Now, substituting the values of admittance into the nodal equations, we get(0.5j0.5)V₁ - (-j0.5)V₂ = 120°Node 1:Node 2:-(-j0.5)V₁ + (-j0.25)V₂ = -220°which, when solved, results in:andV₁ = 4.243 VZ135°V2 = 6.324 VZ-161.57°Ic1₂ = 2 AZ0°ⒸCengage Learning 2013

As per Kirchoff's current law, the net current incoming at any junction will be equal to the net…

VI I₁ = 1 AZ0° IB Y₂ Y₁ IA Y3 Y₁ = 0.5 S Y₂ = -10.5 S Y3 = +1 0.25 S FIGURE 19-22 Now, substituting the values of admittance into the nodal equations, we get (0.5j0.5)V₁ - (-j0.5)V2 = 120° Node 1: Node 2: -(-j0.5)V₁ + (-j0.25)V₂ = -220° which, when solved, results in: and V₂ V₁ = 4.243 VZ135° V₂ = 6.324 VZ-161.57° Ic 1₂ = 2 AZ0° Cengage Learning 2013

VI I₁ = 1 AZ0° IB Y₂ Y₁ IA Y3 Y₁ = 0.5 S Y₂ = -10.5 S Y3 = +1 0.25 S FIGURE 19-22 Now, substituting the values of admittance into the nodal equations, we get (0.5j0.5)V₁ - (-j0.5)V2 = 120° Node 1: Node 2: -(-j0.5)V₁ + (-j0.25)V₂ = -220° which, when solved, results in: and V₂ V₁ = 4.243 VZ135° V₂ = 6.324 VZ-161.57° Ic 1₂ = 2 AZ0° Cengage Learning 2013

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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