240 V 60Hz ( Given : Z₁ N Z2 Z3 Z4 Zs Z6 NNNN H = 15 = = N Z₁ 5+j62 3- j62 10 +12 8 + j42 2+j3n 5 + 10 Z₂ (~ 180 V 60 Hz Z3 Z4 V1 = 240 V V2. 180 V V3 = 200 V Zs Z6 (~) 200v 60Hz f = 60 Hz

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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Solve the power triangle at Z6 using the following network law below.

1.) Kirchoff's Law

Given:
V= 2400° V60 Hz
V2 = 1800° V60 Hz
V3 = 2000° V60 Hz
Z1 = 5+j6 ohms
Z2 = 3-j6 ohms
Z3 = 10+j12 ohms
Z4 = 8+j4 ohms
Z5 = 2+j3 ohms
Z6 = 5+j10 ohms

Note: Please include a step-by-step explanation. Thanks!!!

240V
60Hz
Given :
Z₁
M
Z2
Z3
NNN
Z4
Zs
NN
Z6
H
=
13
"1.
=
11
N
Z₁
5+j62
3- j62
10 +12
8 + j42
2+j32
5 + 10
Z₂
N
~
180 V
60 Hz
Z3
N
Z4
V₁ =
240 V
V₂2 180 V
a
V3 = 200 V
N
Zs
Z6
(~200 v
60Hz
f = 60 Hz
Transcribed Image Text:240V 60Hz Given : Z₁ M Z2 Z3 NNN Z4 Zs NN Z6 H = 13 "1. = 11 N Z₁ 5+j62 3- j62 10 +12 8 + j42 2+j32 5 + 10 Z₂ N ~ 180 V 60 Hz Z3 N Z4 V₁ = 240 V V₂2 180 V a V3 = 200 V N Zs Z6 (~200 v 60Hz f = 60 Hz
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