VI and V₂ : V₁ = 53. 914 L25.5° V₂ = 53. 988 4²9.7" SOLVE FOR Answer should be :

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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question
Given
100 10°
SA
V₁
I
9
V₂
USE
10 230
35
345
Applying Kez @ node 1 (V₁):
V₁ - 1000
V₁
V₁-V2 = 0
+
+
5
3+j4
V₁ [ = + 3+ 4+ = √5] + V² [ ]
V₂
=
100 40°
5
Equation Ⓒ
5
Applying kel@ hode 2 (V₂):
V
+
=
10 230
5
-js
Vz
=
•[=] + v₂ [ + + + + ]· 10/230° → liquation @2
5
SOLVE FOR
VI and V₂ :
Answer should be :
V₁.
53. 914 L25.5°
-
V₂ = 53. 988 429.7"
7
Transcribed Image Text:Given 100 10° SA V₁ I 9 V₂ USE 10 230 35 345 Applying Kez @ node 1 (V₁): V₁ - 1000 V₁ V₁-V2 = 0 + + 5 3+j4 V₁ [ = + 3+ 4+ = √5] + V² [ ] V₂ = 100 40° 5 Equation Ⓒ 5 Applying kel@ hode 2 (V₂): V + = 10 230 5 -js Vz = •[=] + v₂ [ + + + + ]· 10/230° → liquation @2 5 SOLVE FOR VI and V₂ : Answer should be : V₁. 53. 914 L25.5° - V₂ = 53. 988 429.7" 7
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