Suppose that insurance companies did a survey. They randomly surveyed 430 drivers and found that 350 claimed they always buckle up. We are interested in the population proportion of drivers who claim they always buckle up.NOTE: If you are using a Student's t-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) O Part (C)Which distribution should you use for this problem? (Round your answer to four decimal places.)P'- n430Enter a number.Explain your choice.The Student's t-distribution should be used because we do not know the standard deviation.The Student's t-distribution should be used because npq s 10, which implies a small sample.The binomial distribution should be used because there are two outcomes, buckle up or do not buckle up.The normal distribution should be used because we are interested in proportions and the sample size is large.Correct! We use the standard normal distribution to create confidence intervals about the population proportion.O Part (d)Construct a 95% confidence interval for the population proportion who claim they always buckle up.(1) State the confidence interval. (Round your answers to four decimal places.)(ii) Sketch the graph.aaC.L. =2P'(ii) Calculate the error bound. (Round your answer to four decimal places.) (iii) Round your answer to four decimal places.(rounded to four decimal places)p'=

The distribution we should use for the problem is, N(350.0200, 65.1037) Where, mean = np =…

Answered: Vhich distribution should you use for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that insurance companies did a survey. They randomly surveyed 430 drivers and found that 350 claimed they always buckle up. We are interested in the population proportion of drivers who claim they always buckle up.

NOTE: If you are using a Student's t-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.)

O Part (C)
Which distribution should you use for this problem? (Round your answer to four decimal places.)
P'- n
430
Enter a number.
Explain your choice.
The Student's t-distribution should be used because we do not know the standard deviation.
The Student's t-distribution should be used because npq s 10, which implies a small sample.
The binomial distribution should be used because there are two outcomes, buckle up or do not buckle up.
The normal distribution should be used because we are interested in proportions and the sample size is large.
Correct! We use the standard normal distribution to create confidence intervals about the population proportion.
O Part (d)
Construct a 95% confidence interval for the population proportion who claim they always buckle up.
(1) State the confidence interval. (Round your answers to four decimal places.)
(ii) Sketch the graph.
a
a
C.L. =
2
P'
(ii) Calculate the error bound. (Round your answer to four decimal places.)

(iii) Round your answer to four decimal places.
(rounded to four decimal places)
p'=

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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