Inverse MatrixTo find the inverse of the matrix1-1A =1-1-6231-1 01 0 0Begin by adjoining the identity matrix to A to form the following matrixR2 + Rn → R21-3-31-10 1 0I] =1-110 1-2-4 -1-630 0 1to obtain [I | A-1], we apply elementary row operations in the following way1-11 0 0R2 + (-1) R1 → R21-1-1 1-630 0 1In the above row operation, what is the value of nin R,?Note f arise, input exact fractions. For example, if your answer is - write -2/3.

A=1-1010-1-623 To find : Value of n in Rn.

verse Matrix find the inverse of the matrix - -1 A = 1 -1 -6 1 -1 1 ngin by adjoining the identity matrix to A to form the following matrix R2 + R, → R2 1 -3 -3 -1 0100 0 -10 1 0 30 01 -1 | I= 1 1 -2 -4 -1 -6 obtain [I | A), we apply elementary row operations in the following way 1 -1 100 R +(-1) R, + R -1-1 6 2 3 0 01 In the above row operation, what is the value of nin R? ote H arise, input exact fractions. For example, if your answer is - write -2/3.

verse Matrix find the inverse of the matrix - -1 A = 1 -1 -6 1 -1 1 ngin by adjoining the identity matrix to A to form the following matrix R2 + R, → R2 1 -3 -3 -1 0100 0 -10 1 0 30 01 -1 | I= 1 1 -2 -4 -1 -6 obtain [I | A), we apply elementary row operations in the following way 1 -1 100 R +(-1) R, + R -1-1 6 2 3 0 01 In the above row operation, what is the value of nin R? ote H arise, input exact fractions. For example, if your answer is - write -2/3.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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