Verify the identity algebraically. Use the table feature of a graphing utility to check your result numerically. (Simplify at each step.) 1 + cos(8) sin(Ⓒ) + sin(8) 1 + cos(8) = 2 csc(0) 1 + cos(8) + sin²(0) sin(8) sin(0) (1 + cos(0)) + cos²(0) + sin²(Ⓒ) + sin(8) 1 + cos(8) 2+2 sin()(1+cos()) sin(0)(1+ cos()) sin(e)(1+ cos(Ⓒ)) 2 sin(8) 2 csc(0)
Verify the identity algebraically. Use the table feature of a graphing utility to check your result numerically. (Simplify at each step.) 1 + cos(8) sin(Ⓒ) + sin(8) 1 + cos(8) = 2 csc(0) 1 + cos(8) + sin²(0) sin(8) sin(0) (1 + cos(0)) + cos²(0) + sin²(Ⓒ) + sin(8) 1 + cos(8) 2+2 sin()(1+cos()) sin(0)(1+ cos()) sin(e)(1+ cos(Ⓒ)) 2 sin(8) 2 csc(0)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:Verify the identity algebraically. Use the table feature of a graphing utility to check your result numerically. (Simplify at each step.)
1 + cos(8)
+
sin(8)
1 + cos(8)
= 2 csc(0)
sin(Ⓒ)
1 + cos(8)
+ sin²(0)
sin(8)
+ cos²(e) + sin²(Ⓒ)
+
sin(8)
1 + cos(8)
2+2
sin(0)(1+cos())
sin()(1+cos(Ⓒ))
sin()(1+ cos(Ⓒ))
sin(e)(1+ cos(Ⓒ))
2
sin(8)
2 csc(0)
![Describe the errors.
1 + sec(-0)
sin(-8) + tan(-0)
sin
(sin 8)[1
1 sec e
sin (1 sec )
1
sin e
= csc 8
O The first line claims that sec(-) = -sec , sin(-0) = sin 8, and tan(-) = -tan 8. The correct substitutions are sec(-0) = sec 8, sin(-8)= -sin 8, and tan(-) = tan 8.
O The first line claims that sec(-0) = -sece and sin(-) = sin 8. The correct substitutions are sec(-8)= sec and sin(-8)= -sin 8.
O The first line claims that sec(-0) = -sec and tan(-8)= -tan 8. The correct substitutions are sec(-) = sec 0 and tan(-) = tan 8.
O The first line claims that sin(-) = sine and tan(-8)= -tan 8. The correct substitutions are sin(-0) = -sin @ and tan(-8)= tan 8.
1
sec e
- tan e
1- sec 0
(1/cos )]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65353392-d778-436a-b89b-84d4b246e26e%2F9ad71612-1c77-4361-b60f-ff756f47ce0d%2Fajwfa7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Describe the errors.
1 + sec(-0)
sin(-8) + tan(-0)
sin
(sin 8)[1
1 sec e
sin (1 sec )
1
sin e
= csc 8
O The first line claims that sec(-) = -sec , sin(-0) = sin 8, and tan(-) = -tan 8. The correct substitutions are sec(-0) = sec 8, sin(-8)= -sin 8, and tan(-) = tan 8.
O The first line claims that sec(-0) = -sece and sin(-) = sin 8. The correct substitutions are sec(-8)= sec and sin(-8)= -sin 8.
O The first line claims that sec(-0) = -sec and tan(-8)= -tan 8. The correct substitutions are sec(-) = sec 0 and tan(-) = tan 8.
O The first line claims that sin(-) = sine and tan(-8)= -tan 8. The correct substitutions are sin(-0) = -sin @ and tan(-8)= tan 8.
1
sec e
- tan e
1- sec 0
(1/cos )]
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