Verify that the equation is an identity. 1 1 1- sin x 1+ sin x COS

Q: 2 cos^2 x-sin x -1=0

A: 2cos2x-sinx-1=0⇒1-sinx-2sin2x=0⇒sinx=-1, sinx=12⇒x=3π2+2πn, x=π6+2πn, x=5π6+2πn

Q: how to verify (1-2cos^2x)/(1-2cosxsinx) = (sinx+cosx)/(sinx-cosx)

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Q: -(sin^2 θ + cos^2 θ)

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Q: ((sec^(2)x-1)(cotx))/(tanxsinx+cosx)

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Q: sin^4x - cos^4x/sin^2x - cosx =1. prove the identity.

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Q: If sinx^2 =a/b find cos(90-x)

A: See the details solution in below I am consider  sin(x^2 )

Q: solve (sinx)sec^2(x)+(cos x)cosec^2 (x)=0

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Q: How did you get the rewrite from sin^2(x)/sqrt(1+cos(x))

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Q: cos2x

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Q: cscxdx 5+ cos²x sin²x

A: Evaluate: I=∫csc2x5+cos2xsin2xdx We know that, cos xsin x=cot x Then, we have I=∫csc2x5+cot2xdx

Q: which of these possible solutions for cos^2x +n sin^2x - 1 = 0 in the interval x R [0,2pi]

A: This question is based on Trigonometric equation.

Q: (1/cot^2(x))-(1/cos^2(x))

A: We have to simplyfing this

Q: Find the point of intersection of cos(x)=cos^-1(x)

A: We will find the point of intersection using the graph.

Q: Why is cos(sin^-1(x)) equal to sqrt(1-x^2)?

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Q: f(x)=2cos^2 x-1 , 1-2sin^2 x , cos^2 x-sin^2 x and cos2x Make a comparison of the four expressions

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Q: (Sin X-cos X)^2=1-sin 2x

A: Formulae to note: (a-b)2=a2+b2-2ab. 2 sin x cos x=sin2x. Sin2x+Cos2x=1.

Q: sin[cos^-1(12/13)+tan^-1(4/3)]

A: Given:

Q: (cos^4 x) - (sin^4 x) = cos2x   verify the identity

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Q: prove identity cos^4 (A) -sin^4 (A) = 1 - 2 sin^2(A)

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