Verify that λ; is an eigenvalue of A and that x; is a corresponding eigenvector. A₁ = 5, x₁ = (1, 2, -1) A₂ = -3, x₂ = (-2, 10) A3 = -3, x3 = (3, 0, 1) Ax1 = Ax2= Ax3 = A = -2 -2 -1 -2 -2 -1 -2 2 -3 2 1 -6 -2 2 -3 2 1 -6 0 -1 -2 2 = DE 2 -3 2 1 -6 0 -1 -2 IJ 0 2-3 3 I 2 1 -6 0 = E 5 = -3 N7 2 -1- 3 -3 0 = 2₁x1₁ = 1₂x2 = 13x3
Verify that λ; is an eigenvalue of A and that x; is a corresponding eigenvector. A₁ = 5, x₁ = (1, 2, -1) A₂ = -3, x₂ = (-2, 10) A3 = -3, x3 = (3, 0, 1) Ax1 = Ax2= Ax3 = A = -2 -2 -1 -2 -2 -1 -2 2 -3 2 1 -6 -2 2 -3 2 1 -6 0 -1 -2 2 = DE 2 -3 2 1 -6 0 -1 -2 IJ 0 2-3 3 I 2 1 -6 0 = E 5 = -3 N7 2 -1- 3 -3 0 = 2₁x1₁ = 1₂x2 = 13x3
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.1: Eigenvalues And Eigenvectors
Problem 66E: Show that A=[0110] has no real eigenvalues.
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