Express your solution in 4 decimal places. Water flows steadily from point 1, where the diameter is 1 ft., to point 2, where the diameter is 2 ft, at the rate of13.2 ft3/s. The pressure head at 1 is 20 ft. Neglecting loss of energy from 1 to 2, calculate(a) the velocity (ft/s) at point 1,(b) the velocity (ft/s) at point 2, and(c) the pressure head (ft) at 2.(d) If the pressure head at 1 is doubled while all other parameters remain constant including the computedpressure head at 2, what is the head loss (ft) between 1 and 2?25 ft10 ftdatum

Q=A1v1=A2v213.2=π412×v1=π422×v2v1=13.2π412=16.8067ftsv2=13.2π422=4.2016fts

velocity (ft/s) at point 1, velocity (ft/s) at point 2, and pressure head (ft) at 2. e pressure head at 1 is doubled while all other parameters remain constant including the ssure head at 2, what is the head loss (ft) between 1 and 2?

velocity (ft/s) at point 1, velocity (ft/s) at point 2, and pressure head (ft) at 2. e pressure head at 1 is doubled while all other parameters remain constant including the ssure head at 2, what is the head loss (ft) between 1 and 2?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Alloys

An alloy is an admixture of two or more metals or a metal and a non-metal. Since ancient times, man has been using alloys. Alloying helps to retain the properties of the parent matter, such as hardness, strength, toughness, ductility and is corrosion-resistant. Copper alloys such as brass have antimicrobial properties that help to fight against (Coronavirus disease 2019) COVID-19 and other hospital-acquired infections. Some common alloys are brass, bronze, solder steel, etc. Most alloys have a lower melting point than their constituents. This is due to the presence of a nonmetal as one of the constituents that behaves as an impurity and restricts the raise of melting point.

Question

Express your solution in 4 decimal places.

Water flows steadily from point 1, where the diameter is 1 ft., to point 2, where the diameter is 2 ft, at the rate of
13.2 ft3/s. The pressure head at 1 is 20 ft. Neglecting loss of energy from 1 to 2, calculate
(a) the velocity (ft/s) at point 1,
(b) the velocity (ft/s) at point 2, and
(c) the pressure head (ft) at 2.
(d) If the pressure head at 1 is doubled while all other parameters remain constant including the computed
pressure head at 2, what is the head loss (ft) between 1 and 2?
25 ft
10 ft
datum

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