velocity at the point of origin
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Answers should be in 3 decimal places.
The equation of motion of a particle is s = 8t2 + 3t – 10, where s is in meters and t in seconds. Find the velocity at the point of origin (in m/s).
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- A student drove to the university from her home and noted that the odometer reading of her car increased by 12.0 km. The trip took 17.9 min. a.If the straight-line distance from her home to the university is 10.310.3 km in a direction 28.028.0º south of east, what was her average velocity? (magnitude and direction south of east) b.If she returned home by the same path 6.50h after she left, what was her average speed for the entire trip?Please answer all the partsPls help ASAP
- Find the following for path A in the figure below. (For each answer, enter a number.) A 0 (a) the distance traveled (in m) m t с D (c) the displacement (in m) from start to finish m B 24 68 8 10 12 displacement x (m) (b) the magnitude of the displacement (in m) from start to finish m iTutorial Exercise A soccer ball is kicked from 2 feet above the ground. The height, h, in feet of the ball after t seconds is given by the function h = -16t2 + 64t + 2. (a) Graph the function. (b) At what time(s) is the height of the ball 50 feet? Step 1 Create a table of values for the function. [AlgUns.0386] The height function is h = -16t2 + 64t + 2. Create a table of values for the ordered pairs of the form (t, h). th = -16t² + 64t + 2 %3D 1 2 4 Submit Skip (you cannot come back)I don't understand how to do this problem. I tried taking the derivative, but that didn't give me the correct answer. I would really appreciate the help. When a 1984 Alpha Romeo Spider sports car accelerates in the x-direction at the maximum possible rate,its motion during the first 20. seconds is extremely well modeled by the simple equation vx2=(60 m2/s3)t, where t is time in seconds and vx is in m/s. In other words, the squareof teh car's velocity increases linearly with time. What is its acceleration after 3s, assuming that the car starts from rest at t=0 s?
- D = (oxt) + (1/2 * 8.93* (4.7)2) I D = 98.63 meter 5. You are about to skateboard down a long hill. Your initial velocity is 2.0 m/s south. When you reach the bottom of the hill you are travelling 6.0 m/s south. It took you 57 seconds to reach the bottom of the hill. What was your displacement?Pls help ASAPPls help ASAP