For this problem, assume the values on the axes of the graph have 1 decimal place of precision when measured.An athlete is training on a 100 m long linear track. His motion is described by the graph of his position vs. time, below. ### Understanding Velocity in Graph Segments#### (a) Segment AnalysisFor each segment of the graph, determine the athlete’s velocity magnitude and direction:- **Segment A:** - **Magnitude \( v_A \):** Input is 4.0 m/s, marked as incorrect. - **Direction \( v_A \):** Positive x, marked as correct.- **Segment B:** - **Magnitude \( v_B \):** Input is 0 m/s, marked as correct. - **Direction \( v_B \):** The magnitude is zero, marked as correct.- **Segment C:** - **Magnitude \( v_C \):** Input is 4.0 m/s, marked as incorrect. - **Direction \( v_C \):** Negative x, marked as correct.- **Segment D:** - **Magnitude \( v_D \):** Input is 4.0 m/s, marked as incorrect. - **Direction \( v_D \):** Positive x, marked as correct.#### (b) Average VelocityCalculate the athlete's average velocity over a 60-second interval:- **Magnitude:** Input is 4.0 m/s, marked as incorrect.- **Direction:** Positive x, marked as correct.### ExplanationThis exercise focuses on analyzing segments of a velocity graph. Errors in magnitude indicate a need for reevaluation of calculations based on the graph details. Understanding zero magnitude in segment B helps interpret periods of rest. The correct direction selections guide comprehension of directional changes throughout the athlete's movement. The image shows a graph depicting the movement of an object over time, with distance on the y-axis and time on the x-axis. The y-axis is labeled \(x(m)\) representing distance in meters, while the x-axis is labeled \(t(s)\) indicating time in seconds. The graph is structured as follows:- **Segment A (0 to 15 seconds):** The graph starts at the origin (0, 0), and the object moves in a positive direction from 0 to 60 meters over the first 15 seconds. This indicates a uniform motion with a steady increase in distance.- **Segment B (15 to 25 seconds):** From 15 to 25 seconds, the graph is flat at 60 meters, reflecting that the object is stationary during this interval as there is no change in distance over time.- **Segment C (25 to 40 seconds):** Between 25 and 40 seconds, the graph slopes downwards from 60 meters to 40 meters, indicating the object is moving backward or returning toward the starting point.- **Segment D (40 to 60 seconds):** In the final segment, from 40 to 60 seconds, the graph shows a steep upward trajectory from 40 meters to 100 meters. This suggests the object is moving forward quickly, covering more distance in a shorter time span.The graph is divided into sections marked by the letters A, B, C, and D for ease of reference, illustrating different phases of motion over the course of 60 seconds.

Slope of position time graph is velocity. Straight line have constant slope. For constant slope…

For this problem, assume the values on the axes of the graph have 1 decimal place of precision when measured. An athlete is training on a 100 m long linear track. His motion is described by the graph of his position vs. time, below.

For this problem, assume the values on the axes of the graph have 1 decimal place of precision when measured. An athlete is training on a 100 m long linear track. His motion is described by the graph of his position vs. time, below.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

0 Assume that friction is so small that it can be ignored. If you think that none is correct, answer choice J. A force is applied to the car. Choose the one force graph (A through H) for the statement below which could allow the described motion of the car to continue. The car is at rest. B C F 0 I C e FOL C e O с e + + 0 0 1 + Time Time Time +
Hi I am in phyiscs I and it has the problem a runner ran the marathon (approx. 26.1) in 2 hours and 57 min. What was the average speed of the runner in m/s? I understand that I would have to divide the total distance by the total time, but I'm not sure how they changed the miles to meters. Please detalied steps of how to solve this so I can understand it. Thank you!
Please answer all the parts
SOLVE STEP BY STEP IN DIGITAL FORMAT 14. If the speed in (m/s) that a certain athlete reaches in a 200-meter race is described by the function v(x) =-0.005x(x - 300), where x is the recommended distance. a) What distance has the athlete traveled when he reaches his maximum speed?b) What is the maximum speed he reaches?
If an average-size man jumps from an airplane with an open parachute, his downward velocity t seconds into the fall is v(t) = 20(10.2) feet per second. (a) Use functional notation to express the velocity 3 seconds into the fall. Calculate it. ft per sec (b) Explain how the velocity increases with time. Include in your explanation the average rate of change from the beginning of the fall to the end of the first second and the average rate of " change from the fourth second to the fifth second of the fall. This answer has not been graded yet. (c)-Find the terminal velocity. ft per sec (d) Compare the time it takes to reach 99% of terminal velocity here with the 25 seconds it took a skydiver with his parachute closed to reach 99% of terminal velocity in Example 2.1. On the basis of the information we have, which would you expect to reach 99% of terminal velocity first, O feather feather or a cannonball? O cannonball Need Help? Read It
Find the following for path A in the figure below. (For each answer, enter a number.) A 0 (a) the distance traveled (in m) m t с D (c) the displacement (in m) from start to finish m B 24 68 8 10 12 displacement x (m) (b) the magnitude of the displacement (in m) from start to finish m i
Pls help ASAP
Pls help ASAP
Help, I think the answer is the 5th choice, but I am not sure.
What is the equation for the error of D in the following equation, where g is a constant: D = ?
Using the results from part (c), what was the cars horizontal component of acceleration, in meter per second squared, during the braking period ? C=2.75
A ball moves along a 1D coordinate system with the following motion parameters at time t = 0 s: x₁ = 1.9 m and vo = 0 m/s. The ball has a constant acceleration of 1.1 m/s2 during the entire motion which occurs over a time of 1.2 s. Assume that an error in position of 4% is acceptable in this application over the entire motion. How many rows N will be needed in the table to model the entire motion to within the required error even though you are leaving out the final term of 1/2 a (At )²) present in the exact position expression?