vecter u =(=1,0,k) v= (6,-4,2). whit is velne of K for which two nectes are
Angles in Circles
Angles within a circle are feasible to create with the help of different properties of the circle such as radii, tangents, and chords. The radius is the distance from the center of the circle to the circumference of the circle. A tangent is a line made perpendicular to the radius through its endpoint placed on the circle as well as the line drawn at right angles to a tangent across the point of contact when the circle passes through the center of the circle. The chord is a line segment with its endpoints on the circle. A secant line or secant is the infinite extension of the chord.
Arcs in Circles
A circular arc is the arc of a circle formed by two distinct points. It is a section or segment of the circumference of a circle. A straight line passing through the center connecting the two distinct ends of the arc is termed a semi-circular arc.
see attached
![Certainly! Here is the transcribed text from the image suitable for an educational website:
---
### Problem Statement
We are given the following vectors:
- **Vector \( \mathbf{u} \)**
\[ \mathbf{u} = (1, -1, k) \]
- **Vector \( \mathbf{v} \)**
\[ \mathbf{v} = (k, -1, 2) \]
**Question:**
What is the value of \( k \) for which the two vectors are orthogonal?
---
### Explanation:
To determine the value of \( k \) for which the two vectors \(\mathbf{u}\) and \(\mathbf{v}\) are orthogonal, we need to recall the definition of orthogonality in terms of the dot product. Two vectors are orthogonal if and only if their dot product is zero.
The dot product of \(\mathbf{u}\) and \(\mathbf{v}\) is given by:
\[ \mathbf{u} \cdot \mathbf{v} = 1 \cdot k + (-1) \cdot (-1) + k \cdot 2 \]
Simplifying this,
\[ \mathbf{u} \cdot \mathbf{v} = k + 1 + 2k = 3k + 1 \]
For the vectors to be orthogonal, the dot product must be zero:
\[ 3k + 1 = 0 \]
Solving for \( k \):
\[ 3k = -1 \]
\[ k = -\frac{1}{3} \]
Therefore, the value of \( k \) for which the vectors \(\mathbf{u} \) and \(\mathbf{v} \) are orthogonal is \( k = -\frac{1}{3} \).
---
This solves the problem and illustrates the process of finding the value of \( k \) for orthogonality using the dot product of vectors.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faaa612e4-bb6a-4a7c-9bcb-a4980796bdd1%2F206d80cd-2cf6-4f7a-befe-42bb8cab94f1%2Fvm8frb_reoriented.jpeg&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Step by step
Solved in 2 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
![Advanced Engineering Mathematics](https://www.bartleby.com/isbn_cover_images/9780470458365/9780470458365_smallCoverImage.gif)
![Numerical Methods for Engineers](https://www.bartleby.com/isbn_cover_images/9780073397924/9780073397924_smallCoverImage.gif)
![Introductory Mathematics for Engineering Applicat…](https://www.bartleby.com/isbn_cover_images/9781118141809/9781118141809_smallCoverImage.gif)
![Advanced Engineering Mathematics](https://www.bartleby.com/isbn_cover_images/9780470458365/9780470458365_smallCoverImage.gif)
![Numerical Methods for Engineers](https://www.bartleby.com/isbn_cover_images/9780073397924/9780073397924_smallCoverImage.gif)
![Introductory Mathematics for Engineering Applicat…](https://www.bartleby.com/isbn_cover_images/9781118141809/9781118141809_smallCoverImage.gif)
![Mathematics For Machine Technology](https://www.bartleby.com/isbn_cover_images/9781337798310/9781337798310_smallCoverImage.jpg)
![Basic Technical Mathematics](https://www.bartleby.com/isbn_cover_images/9780134437705/9780134437705_smallCoverImage.gif)
![Topology](https://www.bartleby.com/isbn_cover_images/9780134689517/9780134689517_smallCoverImage.gif)