VEB 25 mr V 0.3= VEB + VÓ VEB 0.3 V l014 UEB/ 26x10-3 e 3x 1013= UEB t VEB/26 x/0-3 In(3x10"): In (UEB +(e e) VEB/26x03
VEB 25 mr V 0.3= VEB + VÓ VEB 0.3 V l014 UEB/ 26x10-3 e 3x 1013= UEB t VEB/26 x/0-3 In(3x10"): In (UEB +(e e) VEB/26x03
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What steps did they do to get VEB to be 3 volts? Are you supposed to subtract VEB before taking the ln of both sides? I put my process so you can see where I got stuck.
Transcribed Image Text:-4 VER
> 0.3 = VEß + 16
V
VEB 2 0.3 v
e
1014
UEB/26x10-3
e
3x 1013 = UEB +
UEB/26X10-3
In(3w10"): In(VEo t(e
VEB/26x03
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