VE M2 where Therefore твув M₁ = MA+MB3 = M₂ - ME VB = MATMB VE 2MB 2VE

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Can you explain part b I attached the solution I don’t understand what they are doing with the formula of conservation of linear momentum why are there two types of Mf and MF
Problem 2: Rocket propulsion, two-stage rocket, escape velocity
with
(a) A fully fueled rocket has initial mass Mo, of which Mr is the mass of the fuel. The rocket launched
a given constant velocity, Viel, and at
vertically upward with initial velocity vo = 0. fuel is ejected
burnout time, t-too, the rocket reaches velocity 4₂. = VE, where VE is the escape
of planet Earth. Find a formula for the burnout time, too (no numbers needed)
velocity from the surface
bo
2
bo
* Mo= mass of fully fueled rocket Mr = mass
of fuel
The rocket velocity
a function of time is v(t) = vo - gt + vrel-
as a
At burnout time, M(tbo) = M₁-MF; set V(0) = 0
fully
fueled
rocket
; Vrel = fuel ejected at est velocity
ln MCĐ
Mo
mass
of
fuel
=
vallo (1-1)-9
но зд
g
b
Yoo = -gt bot vrel In (1- ME) ⇒ Vbo = VE ⇒ VE = - gtbo + vurel In (1-MF) <-divide by g
bo
2
2
isolate bo
(6) At burnout time, a prearranged explosion seperates the rocket into two parts, with part A stopped in
midair by the prearranged explosion, while part B is propelled to a velocity VB7VE. Assuming
MA/MB = 3, find the velocity of part B after the explosion.
a mass ratio,
Transcribed Image Text:Problem 2: Rocket propulsion, two-stage rocket, escape velocity with (a) A fully fueled rocket has initial mass Mo, of which Mr is the mass of the fuel. The rocket launched a given constant velocity, Viel, and at vertically upward with initial velocity vo = 0. fuel is ejected burnout time, t-too, the rocket reaches velocity 4₂. = VE, where VE is the escape of planet Earth. Find a formula for the burnout time, too (no numbers needed) velocity from the surface bo 2 bo * Mo= mass of fully fueled rocket Mr = mass of fuel The rocket velocity a function of time is v(t) = vo - gt + vrel- as a At burnout time, M(tbo) = M₁-MF; set V(0) = 0 fully fueled rocket ; Vrel = fuel ejected at est velocity ln MCĐ Mo mass of fuel = vallo (1-1)-9 но зд g b Yoo = -gt bot vrel In (1- ME) ⇒ Vbo = VE ⇒ VE = - gtbo + vurel In (1-MF) <-divide by g bo 2 2 isolate bo (6) At burnout time, a prearranged explosion seperates the rocket into two parts, with part A stopped in midair by the prearranged explosion, while part B is propelled to a velocity VB7VE. Assuming MA/MB = 3, find the velocity of part B after the explosion. a mass ratio,
VE
29
(b) Use conservation of lineal momentum:
tbo
VE
ME 2
where
Therefore
mBVB
M₂ = MA+MB3
VB
-
= M₁-M=
MATMA VE = 2VE
2MB
-2-
The
Transcribed Image Text:VE 29 (b) Use conservation of lineal momentum: tbo VE ME 2 where Therefore mBVB M₂ = MA+MB3 VB - = M₁-M= MATMA VE = 2VE 2MB -2- The
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