vc(t) t =0 C V1 R R2 For the above circuit, the switch has been open for a very long time and then at t= 0 the switch is closed. Given the following component values for the circuit h=4A V = 14 V C=2.7 F R =60 R2=72 Determine the the time constant T after the switch happens. Round your answer to the nearest single digit decimal. Find T in secs (due not enter the units). A Movine to another auestion will save this resoonse. P Type here to search 53°F

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The image shows a circuit diagram and a problem statement related to time constants in electrical circuits. Below is the transcription and explanation for educational purposes:

---

### Circuit Diagram Description

The circuit consists of:

- A DC voltage source \( V_1 \).
- A switch, which has been open for a long time and is closed at \( t = 0 \).
- A resistor \( R_1 \).
- A capacitor \( C \), with voltage \( v_c(t) \) across it.
- A current source \( I_1 \).
- A resistor \( R_2 \).

### Problem Statement

"For the above circuit, the switch has been open for a very long time and then at \( t = 0 \) the switch is closed. Given the following component values for the circuit:

- \( I_1 = 4 \, \text{A} \)
- \( V_1 = 14 \, \text{V} \)
- \( C = 2.7 \, \text{F} \)
- \( R_1 = 6 \, \Omega \)
- \( R_2 = 7 \, \Omega \)

Determine the time constant \( \tau \) after the switch is closed. Round your answer to the nearest single digit decimal.

Find \( \tau \) in seconds (do not enter the units)."

### Explanation of Diagrams

The diagram illustrates a basic RC circuit with both resistive and capacitive components. The switch is crucial in altering the circuit's behavior at \( t = 0 \), enabling the analysis of transient response, particularly relating to how the capacitor charges over time.

**Note:** The time constant \( \tau \) is typically calculated using the formula \( \tau = R_{\text{eq}} \times C \), where \( R_{\text{eq}} \) is the equivalent resistance seen by the capacitor.

---

This setup is useful for understanding transient analysis in RC circuits, emphasizing concepts such as the charging and discharging of capacitors, and applying Ohm’s and Kirchhoff’s laws.
Transcribed Image Text:The image shows a circuit diagram and a problem statement related to time constants in electrical circuits. Below is the transcription and explanation for educational purposes: --- ### Circuit Diagram Description The circuit consists of: - A DC voltage source \( V_1 \). - A switch, which has been open for a long time and is closed at \( t = 0 \). - A resistor \( R_1 \). - A capacitor \( C \), with voltage \( v_c(t) \) across it. - A current source \( I_1 \). - A resistor \( R_2 \). ### Problem Statement "For the above circuit, the switch has been open for a very long time and then at \( t = 0 \) the switch is closed. Given the following component values for the circuit: - \( I_1 = 4 \, \text{A} \) - \( V_1 = 14 \, \text{V} \) - \( C = 2.7 \, \text{F} \) - \( R_1 = 6 \, \Omega \) - \( R_2 = 7 \, \Omega \) Determine the time constant \( \tau \) after the switch is closed. Round your answer to the nearest single digit decimal. Find \( \tau \) in seconds (do not enter the units)." ### Explanation of Diagrams The diagram illustrates a basic RC circuit with both resistive and capacitive components. The switch is crucial in altering the circuit's behavior at \( t = 0 \), enabling the analysis of transient response, particularly relating to how the capacitor charges over time. **Note:** The time constant \( \tau \) is typically calculated using the formula \( \tau = R_{\text{eq}} \times C \), where \( R_{\text{eq}} \) is the equivalent resistance seen by the capacitor. --- This setup is useful for understanding transient analysis in RC circuits, emphasizing concepts such as the charging and discharging of capacitors, and applying Ohm’s and Kirchhoff’s laws.
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