A common-emitter amplifier similar to as shown is operating from a single +20-V power supply, and the emitter terminal is bypassed by capacitor C3. The BJT has βF =100 and VA=50 V and is operating at a Q-point of (100 μA, 10 V). The amplifier has RI = 5 kΩ, RB = 150 kΩ, RC = 100 kΩ, and R3 = ∞. What is the voltage gain predicted from our rule of thumb estimate? What is the actual voltage gain? What is the value of μf for this transistor? Vcc = 12 VR2Rc300 k222 k2R3R1RỊvo1 k2RcR3,1 k2100 k2Rg = R||R222 k2R1.104 k2100 kQREC3→0Signal160 k213 k.source(b)(a)R1R;RgRcRaUbeRBUbeRL VoT&mUbe8m UbeRL(d)Figure 13.18 (a) Common-emitter amplifier circuit employing a bipolar transistor; (b) ac equivalent circuit for the common-emitter amplifier in part (a); the common-emitter connection should now be evident; (c) ac equivalent circuit with the bipolartransistor replaced by its small-signal model; (d) final equivalent circuit for ac analysis of the common-emitter amplifier.

Calculating voltage gain of the common emitter amplifier using rule of thumb estimate Given Q point…

Answered: Vcc = 12 V R2 Rc 300 k2 22 k2 R3 R1 RỊ…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

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A common-emitter amplifier similar to as shown is operating from a single +20-V power supply, and the emitter terminal is bypassed by capacitor C₃. The BJT has β_F =100 and V_A=50 V and is operating at a Q-point of (100 μA, 10 V). The amplifier has R_I = 5 kΩ, R_B = 150 kΩ, R_C = 100 kΩ, and R₃ = ∞. What is the voltage gain predicted from our rule of thumb estimate? What is the actual voltage gain? What is the value of μ_f for this transistor?

Vcc = 12 V
R2
Rc
300 k2
22 k2
R3
R1
RỊ
vo
1 k2
Rc
R3,
1 k2
100 k2
Rg = R||R2
22 k2
R1.
104 k2
100 kQ
RE
C3→0
Signal
160 k2
13 k.
source
(b)
(a)
R1
R;
Rg
Rc
Ra
Ube
RB
Ube
RL Vo
T&mUbe
8m Ube
RL
(d)
Figure 13.18 (a) Common-emitter amplifier circuit employing a bipolar transistor; (b) ac equivalent circuit for the common-
emitter amplifier in part (a); the common-emitter connection should now be evident; (c) ac equivalent circuit with the bipolar
transistor replaced by its small-signal model; (d) final equivalent circuit for ac analysis of the common-emitter amplifier.

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