VB1 IRA || R1 VB2 R2 R5 In the circuit above, the current through R5 (labeled as I3) is 15 mA. Given this information, find the magnitude of the current through the other resistors and the magnitude of the voltage drop across the second battery VB2. Note the WebWork units for current (1) are amp. For resistance, you can use ohm or kohm. VB1 = 3 volts 13= 15 mA R1 = 3400 R2 = 1400 R3 = 1100 R4 = 1200 R5 = 4300 IRI= IR2 = IR3 M 9. 4* 8- 47 R3 ww S www R4 VB2

VB1 IRA || R1 VB2 R2 R5 In the circuit above, the current through R5 (labeled as I3) is 15 mA. Given this information, find the magnitude of the current through the other resistors and the magnitude of the voltage drop across the second battery VB2. Note the WebWork units for current (1) are amp. For resistance, you can use ohm or kohm. VB1 = 3 volts 13= 15 mA R1 = 3400 R2 = 1400 R3 = 1100 R4 = 1200 R5 = 4300 IRI= IR2 = IR3 M 9. 4* 8- 47 R3 ww S www R4 VB2

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

VB1
=
=
RA 120Ω
IRA
G
R5=4300
IR1
IR2 =
IR3
In the circuit above, the current through R5 (labeled as 13) is 15 mA. Given this information, find the magnitude of the current through the other
resistors and the magnitude of the voltage drop across the second battery VB2.
Note the WebWork units for current (1) are amp. For resistance, you can use ohm or kohm.
VB1 = 3 volts
13= 15 mA
R1
340Ω
R2
140Ω
R3 = 1100
=
=
-
R1
www
VB2 =
R2
13
R5
S
R3
www
R4
VB2

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