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Vay (GaAs). 100 V Vivi(Si) 50 V I.(GaAs) 25 204 15 10 5 0.3 0.7 Vg(Ge) __Vr (S) 5 pA Ge 10 pA Si GaAs 1.01.2 VK (GaAs) VD (V

Vay (GaAs). 100 V Vivi(Si) 50 V I.(GaAs) 25 204 15 10 5 0.3 0.7 Vg(Ge) __Vr (S) 5 pA Ge 10 pA Si GaAs 1.01.2 VK (GaAs) VD (V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Hello sir, I have a note of how the numbers are in yellow, how did they get 0.05
Vav (GaAs) 100 V Viv(Si) " I.(GaAs) 50 V 30 25 20 15 10 p(mA) 5 PA 10 pA Hence voltage= 13 x 0.05 = 0.65 V 0.3 0.7 10 12 Vg(Ge) Vc(Si) Vg (GaAs) Ge Si 2 small blocks = 0.1 V, 1 small block = 0.05 V. a) voltage across silicon diode at a current of 2 mA covering 13 small blocks, Hence voltage= 14.5 x 0.05 = 0.725 V GaAs Hence voltage= 16.5 x 0.05 = 0.825 V Vp (V) b) voltage across silicon diode at a current of 5 mA covering 14.5 small blocks, c) voltage across silicon diode at a current of 30 mA covering 16.5 small blocks,
Transcribed Image Text:Vav (GaAs) 100 V Viv(Si) " I.(GaAs) 50 V 30 25 20 15 10 p(mA) 5 PA 10 pA Hence voltage= 13 x 0.05 = 0.65 V 0.3 0.7 10 12 Vg(Ge) Vc(Si) Vg (GaAs) Ge Si 2 small blocks = 0.1 V, 1 small block = 0.05 V. a) voltage across silicon diode at a current of 2 mA covering 13 small blocks, Hence voltage= 14.5 x 0.05 = 0.725 V GaAs Hence voltage= 16.5 x 0.05 = 0.825 V Vp (V) b) voltage across silicon diode at a current of 5 mA covering 14.5 small blocks, c) voltage across silicon diode at a current of 30 mA covering 16.5 small blocks,
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