vaporizes at 100°C or 373.15K, with the enthalpy of steam being AH (40,657 kJ/mol). vape The Gibbs free energy equation is G=H TS or written . • G=AH-TAS So the formation of free energy is AG or A GO AH-TAS ° If AG<0AG<0, then the process occurs spontaneously. If AG=0AG=0 then the system is in equilibrium. If AG>OAG>0, then the process does not occur spontaneously but opposite Calculate the entropy of formation AS and the free energy A,Gº.
vaporizes at 100°C or 373.15K, with the enthalpy of steam being AH (40,657 kJ/mol). vape The Gibbs free energy equation is G=H TS or written . • G=AH-TAS So the formation of free energy is AG or A GO AH-TAS ° If AG<0AG<0, then the process occurs spontaneously. If AG=0AG=0 then the system is in equilibrium. If AG>OAG>0, then the process does not occur spontaneously but opposite Calculate the entropy of formation AS and the free energy A,Gº.
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ISBN:9781305957404
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![vaporizes at 100°C or 373.15K, with the enthalpy of steam being AH
(40,657 kJ/mol).
vape
The Gibbs free energy equation is
G=H TS or written
• G=AH-TAS
So the formation of free energy is AG or
A GO AH-TAS °
If AG<0AG<0, then the process occurs spontaneously.
If AG=0AG=0 then the system is in equilibrium.
If AG>OAG>0, then the process does not occur spontaneously but
opposite
Calculate the entropy of formation AS and the free energy A,Gº.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F59c7fb60-de4b-41d9-95d7-582a67c029a3%2F374d86e0-e988-4048-b620-d0ce963e9d8c%2Fgz2dc6l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:vaporizes at 100°C or 373.15K, with the enthalpy of steam being AH
(40,657 kJ/mol).
vape
The Gibbs free energy equation is
G=H TS or written
• G=AH-TAS
So the formation of free energy is AG or
A GO AH-TAS °
If AG<0AG<0, then the process occurs spontaneously.
If AG=0AG=0 then the system is in equilibrium.
If AG>OAG>0, then the process does not occur spontaneously but
opposite
Calculate the entropy of formation AS and the free energy A,Gº.
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