VAIe =(VBy)₁ = (VBy)₂e=Two pool balls collide as shown. Determine if the equations below are valid to be used along the line ofimpact (x-axis) or along the plane of contact (y-axis) or neither.Equations(VA)2 – (UB)₂(VB)₁- (VA)₁e =("Ay)2 − (UBy)2(UBy) − (PAy)1y(VAZ) 2 - (VBZ) 2(UBI)₁- (UAZ)1VB1|MÂ(VA)₁ +MB(VB)₁ = M₁(VA)₂ +MB(VB)₂]MA(VAz)₁ +MB(VBr)₁ = MA(VAz)₂ +mB(VBr)2(VA)₁ = (v₁)₂| (VAY)₁ = (VAY)₂(VBz)1 = (UBz)220X

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Description: VAIe =(VBy)₁ = (VBy)₂e=Two pool balls collide as shown. Determine if the equations below are valid to be used along the line ofimpact (x-axis) or along the plane of contact (y-axis) or neither.Equations(VA)2 – (UB)₂(VB)₁- (VA)₁e =("Ay)2 − (UBy)2(UBy

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VAI Equations (VA)₂ – (UB)₂ (UB)₁- (VA)₁ |(UBy)₁ - (UBy)₂ e= Two pool balls collide as shown. Determine if the equations below are valid to be used along the line of impact (x-axis) or along the plane of contact (y-axis) or neither. (21y)2 — (PByz (UBy)₁- (VAy)₁ у (VAZ)₂-(UBz)₂ (VBz)₁ - (UAZ)₁ VB1 ✓m₁(VA)₁ +MB(VB)₁ = m₁(VA)₂ + MÂ(VB)₂ ✔MA(VAz)₁ +MB(VB1)1 = MA(VAz)2+MB(VB1)2 ✓(VA)₁- (VA)₂ ✓(VAy)₁- (VAY)₂ ✓(UBz)₁ - (UBz)2 20 X

VAI Equations (VA)₂ – (UB)₂ (UB)₁- (VA)₁ |(UBy)₁ - (UBy)₂ e= Two pool balls collide as shown. Determine if the equations below are valid to be used along the line of impact (x-axis) or along the plane of contact (y-axis) or neither. (21y)2 — (PByz (UBy)₁- (VAy)₁ у (VAZ)₂-(UBz)₂ (VBz)₁ - (UAZ)₁ VB1 ✓m₁(VA)₁ +MB(VB)₁ = m₁(VA)₂ + MÂ(VB)₂ ✔MA(VAz)₁ +MB(VB1)1 = MA(VAz)2+MB(VB1)2 ✓(VA)₁- (VA)₂ ✓(VAy)₁- (VAY)₂ ✓(UBz)₁ - (UBz)2 20 X

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

VAI
e =
(VBy)₁ = (VBy)₂
e=
Two pool balls collide as shown. Determine if the equations below are valid to be used along the line of
impact (x-axis) or along the plane of contact (y-axis) or neither.
Equations
(VA)2 – (UB)₂
(VB)₁- (VA)₁
e =
("Ay)2 − (UBy)2
(UBy) − (PAy)1
y
(VAZ) 2 - (VBZ) 2
(UBI)₁- (UAZ)1
VB1
|MÂ(VA)₁ +MB(VB)₁ = M₁(VA)₂ +MB(VB)₂
]MA(VAz)₁ +MB(VBr)₁ = MA(VAz)₂ +mB(VBr)2
(VA)₁ = (v₁)₂
| (VAY)₁ = (VAY)₂
(VBz)1 = (UBz)2
20
X

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