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V2 i2 R1 R3 V1 + i R4 R2 i3 R5 V3 The analysis of the voltage, V for the electrical circuit shown in figure given above can be expressed in the following three equations: R, (i, - i, ) + R, (4 -i; ) =V R3 i, + R4 (i, – iz)+ R (i, – i¿ ) = V, %3D R; iz + R4 (iz – i, ) + R, (iz – 4 ) = V3 where R is the resistance and i is the current. If R1= 20, R2= 10, R3= 25, = 10, R5= 30, Vi=0, V2=0 and V3=200, Solve the system of linear equations above for i, i, and i, by Gauss elimination R4 method. 3.

V2 i2 R1 R3 V1 + i R4 R2 i3 R5 V3 The analysis of the voltage, V for the electrical circuit shown in figure given above can be expressed in the following three equations: R, (i, - i, ) + R, (4 -i; ) =V R3 i, + R4 (i, – iz)+ R (i, – i¿ ) = V, %3D R; iz + R4 (iz – i, ) + R, (iz – 4 ) = V3 where R is the resistance and i is the current. If R1= 20, R2= 10, R3= 25, = 10, R5= 30, Vi=0, V2=0 and V3=200, Solve the system of linear equations above for i, i, and i, by Gauss elimination R4 method. 3.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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V2 i2 R1 R3 V1 + i R4 R2 i3 R5 V3 The analysis of the voltage, V for the electrical circuit shown in figure given above can be expressed in the following three equations: R(-ち)+ &,(i-ち)=7 R3 i, + R4 (i, – iz)+ R (i, – i¿ ) = V, %3D R; iz + R4 (iz – i, ) + R, (iz – 4 ) = V3 where R is the resistance and i is the current. If R1= 20, R2= 10, R3= 25, = 10, R5= 30, Vi=0, V2=0 and V3=200, Solve the system of linear equations above for i, i, and i, by Gauss elimination R4 method. 3.
Transcribed Image Text:V2 i2 R1 R3 V1 + i R4 R2 i3 R5 V3 The analysis of the voltage, V for the electrical circuit shown in figure given above can be expressed in the following three equations: R(-ち)+ &,(i-ち)=7 R3 i, + R4 (i, – iz)+ R (i, – i¿ ) = V, %3D R; iz + R4 (iz – i, ) + R, (iz – 4 ) = V3 where R is the resistance and i is the current. If R1= 20, R2= 10, R3= 25, = 10, R5= 30, Vi=0, V2=0 and V3=200, Solve the system of linear equations above for i, i, and i, by Gauss elimination R4 method. 3.
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