2 + E1 - b R₁ = 2.2 k E2 + d lx R₂ = ↓ 3.3 ΚΩ R3 = 2.0 ΚΩ Vx Figure 3.0: Circuit with multiple voltage sources
2 + E1 - b R₁ = 2.2 k E2 + d lx R₂ = ↓ 3.3 ΚΩ R3 = 2.0 ΚΩ Vx Figure 3.0: Circuit with multiple voltage sources
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Question
(i) For the circuit shown in Figures 3.0, consider the input D.C. source voltages, E1 = 5V and E2 = 2V (note the polarities of each source!). Determine the values of voltage, VX and current, IX using either the nodal-voltage or the mesh-current analysis technique. Show your analysis below, and record your results in Table 4.0.
(ii) For the same circuit shown in Figures 3.0 with the input D.C. source voltages, E1 = 5V and E2 = 2V, apply the Superposition Principle technique as follows:-
- Remove input source, E2 and replace it with a short-circuit by connecting a wire between “c” and “d”. Determine the resultant voltage, VX1 across R3 and current, IX1 through R3. Show your analysis below, and record the results in Table 4.0.
- Connect input source, E2 in its original place between “c” and “d”. Be mindful of the polarity connections. Then remove input source, E1 and replace it with a short-circuit by connecting a wire between “a” and “b”. Determine the resultant voltage, VX2 across R3 and current, IX2 through R3. Show your analysis below, and record the results in Table 4.0.
![2
+
E1
-
b
R₁ = 2.2 k
E2
+
d
lx
R₂ =
↓
3.3 ΚΩ
R3 =
2.0 ΚΩ
Vx
Figure 3.0: Circuit with multiple voltage sources](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F632e1839-b837-4879-99c0-d00e9d1e2ef3%2F761c5589-4c28-4ba5-9f89-7a78aa85d285%2F2at39bf_processed.png&w=3840&q=75)
Transcribed Image Text:2
+
E1
-
b
R₁ = 2.2 k
E2
+
d
lx
R₂ =
↓
3.3 ΚΩ
R3 =
2.0 ΚΩ
Vx
Figure 3.0: Circuit with multiple voltage sources
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