3.87Kohm, R1 = 5475.00Kohm, R2 = 6525.00Kohm, R3 = 1.90Kohm, R4 = 0.63Kohm, R5 = 22.19ohm, Ry = 82.97Kohm, VCC = 12.00V, VTN = 2.82V, Kn = Since it is 5.13(mA/V^2), C1= 5.56uF, C2=13.32uF, C3= 7.43uF, calculate the lower cutoff frequency of the circuit in
3.87Kohm, R1 = 5475.00Kohm, R2 = 6525.00Kohm, R3 = 1.90Kohm, R4 = 0.63Kohm, R5 = 22.19ohm, Ry = 82.97Kohm, VCC = 12.00V, VTN = 2.82V, Kn = Since it is 5.13(mA/V^2), C1= 5.56uF, C2=13.32uF, C3= 7.43uF, calculate the lower cutoff frequency of the circuit in
Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter17: Commercial And Industrial Air-conditioning Control Systems
Section: Chapter Questions
Problem 22RQ
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In the circuit given in the figure, Rk = 3.87Kohm, R1 = 5475.00Kohm, R2 = 6525.00Kohm, R3 = 1.90Kohm, R4 = 0.63Kohm, R5 = 22.19ohm, Ry = 82.97Kohm, VCC = 12.00V, VTN = 2.82V, Kn = Since it is 5.13(mA/V^2), C1= 5.56uF, C2=13.32uF, C3= 7.43uF, calculate the lower cutoff frequency of the circuit in Hz.
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