v(1) Vm Vm/2 T/4 T/2 3T/4 T 5T/4 Figure P16.4 Full Alternative Text (1)'a Vm /2 37 5T 4 4 (a) v(t) Vm/2 37 5T 4 4 (b) Vz(t + T/8) Vm/2 -т -т о TT 3T T 5T 4 2 (c) 2 4 Figure P16.18 Full Altemative Text
v(1) Vm Vm/2 T/4 T/2 3T/4 T 5T/4 Figure P16.4 Full Alternative Text (1)'a Vm /2 37 5T 4 4 (a) v(t) Vm/2 37 5T 4 4 (b) Vz(t + T/8) Vm/2 -т -т о TT 3T T 5T 4 2 (c) 2 4 Figure P16.18 Full Altemative Text
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
It is sometimes possible to use symmetry to find the Fourier
coefficients, even though the original function is not symmetrical! With
this thought in mind, consider the function P16.4. Observe that
v(t) can be divided into the two functions illustrated in 16.18(a)
and (b). Furthermore, we can make v2(t) an even function by shifting it
T/8 units to the left. This is illustrated in P16.18(c). At this point we note that v(t)=v1(t)+v2(t) and that the Fourier series of v1(t) is a singleterm
series consisting of Vm/2. To find the Fourier series of v2(t), we
first find the Fourier series of v2(t+T/8) and then shift this series T/8
units to the right.
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