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how would I derive Lasas, Lasbs, Larbr, Lasbr, Larar, when g is constantPart B where does the theta come from

how would I derive Lasas, Lasbs, Larbr, Lasbr, Larar, when g is constantPart B where does the theta come from

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Using this form how would I derive Lasas, Lasbs, Larbr, Lasbr, Larar, when g is constant

I know Lasar is W_as and W_ar into the first equation, I am also thinking Lasas is W_x=W_as and W_y =W_as in the first equation.

Part B where does the theta come from. 

Using this form how would I derive Lasas, Lasbs, Larbr, Lasbr, Larar, when g is constant I know Lasar is W as and W ar into the first equation, I am also thinking Lasas is W-x=W as and W y =W_as in the first equation. 2л W;(Ø)Wy(Ø) = Lym = Horl g(ø)| Thus, the winding function may be expressed in terms of electrical stator position as N, Was (9,) = - -cos(ø,) (2.8-10) P N, -cos(ø, – 27 / 3) P Wbs (0, ) = (2.8-11) Wa(9,) =- N, -cos(ø, + 27 / 3) P (2.8-12) for which, making use of the relation (2.3-11) War (4, ) = N, cos(0, ) / P (2.8-47) Wbr (0,) = N, cos(4, – 27 / 3) / P (2.8-48) Wer (0, ) = N, cos(ø, + 27 / 3) / P (2.8-49)
Transcribed Image Text:Using this form how would I derive Lasas, Lasbs, Larbr, Lasbr, Larar, when g is constant I know Lasar is W as and W ar into the first equation, I am also thinking Lasas is W-x=W as and W y =W_as in the first equation. 2л W;(Ø)Wy(Ø) = Lym = Horl g(ø)| Thus, the winding function may be expressed in terms of electrical stator position as N, Was (9,) = - -cos(ø,) (2.8-10) P N, -cos(ø, – 27 / 3) P Wbs (0, ) = (2.8-11) Wa(9,) =- N, -cos(ø, + 27 / 3) P (2.8-12) for which, making use of the relation (2.3-11) War (4, ) = N, cos(0, ) / P (2.8-47) Wbr (0,) = N, cos(4, – 27 / 3) / P (2.8-48) Wer (0, ) = N, cos(ø, + 27 / 3) / P (2.8-49)
Lasar equals to these equation, where does the Theta come from. Horl N, N CoS -cos0,do, P Lasar -coso, (2.8-50) ite this expression directly since ø, and ø, are dependent; using (2.2-6), Horl i N, cos(0, + 0,) cos0,dộ, Lasar N, (2.8-51) P P N, N , μοrlπ Lasar -cos(0,) (2.8-52) РР Derive, Lasas, Lasbs, Larbr, Lasbr, Larar
Transcribed Image Text:Lasar equals to these equation, where does the Theta come from. Horl N, N CoS -cos0,do, P Lasar -coso, (2.8-50) ite this expression directly since ø, and ø, are dependent; using (2.2-6), Horl i N, cos(0, + 0,) cos0,dộ, Lasar N, (2.8-51) P P N, N , μοrlπ Lasar -cos(0,) (2.8-52) РР Derive, Lasas, Lasbs, Larbr, Lasbr, Larar
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