V and a second that measures its radius of curvaturein a perpendicular magnetic field as shown in (Figure1).The ion begins at potential V and is accelerated towardzero potential. When the particle exits the region withthe electric field it will have obtained a speed u.Figure< 1 of 1mAfter being accelerated, the particle enters a uniform magnetic field of strength Bo and travels in acircle of radius R (determined by observing where it hits on a screen--as shown in the figure). Theresults of this experiment allow one to find m/q in terms of the experimentally measured quantitiessuch as the particle radius, the magnetic field, and the applied voltage.What is m/q?>+ + + ++ + +

Given: Radius = R mass=m charge=q Magnetic field=B0

Answered: V and a second that measures its radius…

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The answer is C) 205.36 but I am confused on the steps of how to solve this problem.