**Problem Statement:** A charged body is sliding down an inclined plane in an external magnetic field \( B = 3.5 \, \text{T} \). The body has a charge \( q = -0.25 \, \text{C} \) and a mass \( m = 2.5 \, \text{kg} \). The magnetic field is parallel to the plane and perpendicular to the gravitational field \( g \). The inclination angle of the plane is \( \alpha = 55^\circ \), and the friction coefficient is \( \mu = 0.85 \). Ignore air resistance and take the acceleration due to gravity \( g = 9.81 \, \text{m/s}^2 \). **Objective:** Find the maximum speed the charged body can achieve while sliding down the plane. **Diagram Explanation:** The diagram shows: - An inclined plane with an angle \( \alpha = 55^\circ \). - A block labeled with charge \( q \) and mass \( m \) on the plane. - The gravitational force \( g \) acting downward. - The magnetic field \( B \) indicated as being perpendicular to \( g \) and parallel to the plane surface. **Solution:** The maximum speed, \( v \), is calculated to be \( 18.077 \, \text{m/s} \).

Problem Statement: A charged body is sliding down an inclined plane in an external magnetic field \( B = 3.5 \, \text{T} \). The body has a charge \( q = -0.25 \, \text{C} \) and a mass \( m = 2.5 \, \text{kg} \). The magnetic field is parallel to the plane and perpendicular to the gravitational field \( g \). The inclination angle of the plane is \( \alpha = 55^\circ \), and the friction coefficient is \( \mu = 0.85 \). Ignore air resistance and take the acceleration due to gravity \( g = 9.81 \, \text{m/s}^2 \). Objective: Find the maximum speed the charged body can achieve while sliding down the plane. Diagram Explanation: The diagram shows: - An inclined plane with an angle \( \alpha = 55^\circ \). - A block labeled with charge \( q \) and mass \( m \) on the plane. - The gravitational force \( g \) acting downward. - The magnetic field \( B \) indicated as being perpendicular to \( g \) and parallel to the plane surface. Solution: The maximum speed, \( v \), is calculated to be \( 18.077 \, \text{m/s} \).

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

**Problem Statement:**

A charged body is sliding down an inclined plane in an external magnetic field \( B = 3.5 \, \text{T} \). The body has a charge \( q = -0.25 \, \text{C} \) and a mass \( m = 2.5 \, \text{kg} \). The magnetic field is parallel to the plane and perpendicular to the gravitational field \( g \). The inclination angle of the plane is \( \alpha = 55^\circ \), and the friction coefficient is \( \mu = 0.85 \). Ignore air resistance and take the acceleration due to gravity \( g = 9.81 \, \text{m/s}^2 \).

**Objective:**

Find the maximum speed the charged body can achieve while sliding down the plane.

**Diagram Explanation:**

The diagram shows:
- An inclined plane with an angle \( \alpha = 55^\circ \).
- A block labeled with charge \( q \) and mass \( m \) on the plane.
- The gravitational force \( g \) acting downward.
- The magnetic field \( B \) indicated as being perpendicular to \( g \) and parallel to the plane surface.

**Solution:**

The maximum speed, \( v \), is calculated to be \( 18.077 \, \text{m/s} \).

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