I have to find the theoric part with the given equations R1В12R,R3AFigure 5.3 The electrical circuit with resistances: R1=2.2, R=3.3 ve R3=4.7Kirchhoff sVoltage LawE=IR1+I¡R21s* DirectionE=2,21+3,311RI1+R3I2=02nd Direction3,311+4,712=0E (volt)Vi (volt)V2 (volt)V3 (volt)3 VExperimental 1,594 V1,413 V1,413 VTheoric6 VExperimental 3,174 V2,82 V2,82 VTheoric

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В 12 ww 1 2 R2 R3 A Figure 5.3 The electrical circuit with resistances: R1=2.2, R2=3.3 ve R3=4.7 Kirchhoff s Voltage Law E=IR1+I¡R2 1st Direction E=2,21+3,311 RIi+R3L=0 2nd Direction 3,311+4,712=0 E (volt) Vi (volt) V2 (volt) V3 (volt)

В 12 ww 1 2 R2 R3 A Figure 5.3 The electrical circuit with resistances: R1=2.2, R2=3.3 ve R3=4.7 Kirchhoff s Voltage Law E=IR1+I¡R2 1st Direction E=2,21+3,311 RIi+R3L=0 2nd Direction 3,311+4,712=0 E (volt) Vi (volt) V2 (volt) V3 (volt)

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter28: Direct-current Circuits

Section: Chapter Questions

Problem 28.7CQ

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Question

I have to find the theoric part with the given equations

R1
В
1
2
R,
R3
A
Figure 5.3 The electrical circuit with resistances: R1=2.2, R=3.3 ve R3=4.7
Kirchhoff s
Voltage Law
E=IR1+I¡R2
1s* Direction
E=2,21+3,311
RI1+R3I2=0
2nd Direction
3,311+4,712=0
E (volt)
Vi (volt)
V2 (volt)
V3 (volt)
3 V
Experimental 1,594 V
1,413 V
1,413 V
Theoric
6 V
Experimental 3,174 V
2,82 V
2,82 V
Theoric

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