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ution: p ± Za/2/pq/n= 0.06 ± 1.96/0.06 × 0.94/100 = 0.06 ± 0.046547, or (0.01345, 0.10655)

ution: p ± Za/2/pq/n= 0.06 ± 1.96/0.06 × 0.94/100 = 0.06 ± 0.046547, or (0.01345, 0.10655)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In this question, I don't understand how we got number 1.96 where I have highlighted. Please help me to explain. Thank you. 

Call to technical support service of a software company are monitored on a sampling basis for quality assurance. Each monitored call is classified as satisfactory or unsatisfactory by the supervisor in terms of the quality of help offered. A random sample of 100 calls was monitored over one month for the new trainee; 6 calls were classified as unsatisfactory. (а) Calculate a 95% confidence interval for the actual proportion of unsatisfactory calls during a month. Solution: p ± Za/2/pâ/n = 0.06 ± 1.96/0.06 x 0.94/100 = 0.06 ± 0.046547, or (0.01345, 0.10655)
Transcribed Image Text:Call to technical support service of a software company are monitored on a sampling basis for quality assurance. Each monitored call is classified as satisfactory or unsatisfactory by the supervisor in terms of the quality of help offered. A random sample of 100 calls was monitored over one month for the new trainee; 6 calls were classified as unsatisfactory. (а) Calculate a 95% confidence interval for the actual proportion of unsatisfactory calls during a month. Solution: p ± Za/2/pâ/n = 0.06 ± 1.96/0.06 x 0.94/100 = 0.06 ± 0.046547, or (0.01345, 0.10655)
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