Using von Karman momentum integral, derive boundary layer height 8, boundary layer displacement thickness 84, boundary layer momentum thickness 0, wall shear stress To, local skin friction coefficient c, and total drag coefficient C, for turbulent boundary layer flow with power law constant, n 5. Discuss by comparing your answers to turbulent boundary layer flow with power law constant, n = 7. %3D Take the empirical wall shear stress: To = 0.0204pU %3D SU 14

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Using von Karman momentum integral, derive boundary layer height 8, boundary
layer displacement thickness d, boundary layer momentum thickness 0, wall shear
stress To, local skin friction coefficient c, and total drag coefficient C, for turbulent
boundary layer flow with power law constant, n = 5. Discuss by comparing your
answers to turbulent boundary layer flow with power law constant, n = 7.
Take the empirical wall shear stress:
To = 0.0204pU
2
%3D
SU
1/4
Transcribed Image Text:Using von Karman momentum integral, derive boundary layer height 8, boundary layer displacement thickness d, boundary layer momentum thickness 0, wall shear stress To, local skin friction coefficient c, and total drag coefficient C, for turbulent boundary layer flow with power law constant, n = 5. Discuss by comparing your answers to turbulent boundary layer flow with power law constant, n = 7. Take the empirical wall shear stress: To = 0.0204pU 2 %3D SU 1/4
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