Using this approach, Planck generated a theoretical expression for the wave- length distribution that agreed remarkably well with the experimental curves in Figure 39.3: 2Thc? I(A,T) = (39.6) Let's consider one of these early attempts. To describe the distribution of energy from a black body, we define I(A,T) da to be the intensity, or power per unit area, emitted in the wavelength interval da. The result of a calculation based on a classi- cal theory of blackbody radiation known as the Rayleigh-Jeans law is 2mck,T B I(1,T) = (39.3)

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter6: The Structure Of Atoms
Section: Chapter Questions
Problem 76SCQ
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Show that at long wavelengths, Planck’s radiation law (as shown) reduces to the Rayleigh–Jeans law (as shown).

Using this approach, Planck generated a theoretical expression for the wave-
length distribution that agreed remarkably well with the experimental curves in
Figure 39.3:
2Thc?
I(A,T) =
(39.6)
Transcribed Image Text:Using this approach, Planck generated a theoretical expression for the wave- length distribution that agreed remarkably well with the experimental curves in Figure 39.3: 2Thc? I(A,T) = (39.6)
Let's consider one of these early attempts. To describe the distribution of energy
from a black body, we define I(A,T) da to be the intensity, or power per unit area,
emitted in the wavelength interval da. The result of a calculation based on a classi-
cal theory of blackbody radiation known as the Rayleigh-Jeans law is
2mck,T
B
I(1,T) =
(39.3)
Transcribed Image Text:Let's consider one of these early attempts. To describe the distribution of energy from a black body, we define I(A,T) da to be the intensity, or power per unit area, emitted in the wavelength interval da. The result of a calculation based on a classi- cal theory of blackbody radiation known as the Rayleigh-Jeans law is 2mck,T B I(1,T) = (39.3)
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