Using the substitution y=vxanddy=vdx+xdv, solve the homogeneous differential equation y (2) - Jax- X xsin dx + xdy = 0 y y ℗ x[ex²2²2 - co²-²-) = c A CSC X X y y ℗ x (exe ² - co²=²+ = c B X X y y © > (exe ² + + co₂ = =) = c C y X X D y y X CSC (cse ² + + co₁² ) = c X X
Using the substitution y=vxanddy=vdx+xdv, solve the homogeneous differential equation y (2) - Jax- X xsin dx + xdy = 0 y y ℗ x[ex²2²2 - co²-²-) = c A CSC X X y y ℗ x (exe ² - co²=²+ = c B X X y y © > (exe ² + + co₂ = =) = c C y X X D y y X CSC (cse ² + + co₁² ) = c X X
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Using the substitution y=vxanddy=vdx + xdv, solve
the homogeneous differential equation
y
[xsin (--)-> ]dx-
X
y dx + xdy=0
+
y
y
@ x (exe ² - - co₁²-) = c
A
CSC-
X
X
℗ x (exe ² - co₁²-) = c
y
y
B
y csc
X
X
y
Ⓒy[ese ² + +
C
X
Ⓒ₁ x (exe ² + +
y
D
CSC-
X
y
co₁² ) = c
X
y
co₁=² ) = c
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27b9a655-a001-4add-8e21-a753cf870eb4%2Fbde5c346-9c74-4e8d-98d5-d56833d26617%2F8wnw89o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Using the substitution y=vxanddy=vdx + xdv, solve
the homogeneous differential equation
y
[xsin (--)-> ]dx-
X
y dx + xdy=0
+
y
y
@ x (exe ² - - co₁²-) = c
A
CSC-
X
X
℗ x (exe ² - co₁²-) = c
y
y
B
y csc
X
X
y
Ⓒy[ese ² + +
C
X
Ⓒ₁ x (exe ² + +
y
D
CSC-
X
y
co₁² ) = c
X
y
co₁=² ) = c
X
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