Using the substitution u = expressed as an integral in terms of u is given by -1, the definite integral 5 2 2 ° 1² ( ² 0²² - ²3 0²²2 +4 201²/²) + 5/2 -u³/2 +2u¹/2 du 2 3 (5² +2³2 +0³/²) du (25/2 L₁ (125/2. 4 ° /* ( ²3 0²/²2 - 03/1²/²2 + 201¹/²) du [₁₂ x²√x - 1 dx (u5/2+2u³/2+u¹/2) du

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Using the substitution u =
expressed as an integral in terms of u is given by
-1, the definite integral
5
2
2
° 1² ( ² 0²² - ²3 0²²2 +4 201²/²) +
5/2
-u³/2
+2u¹/2
du
2
3
(5² +2³2 +0³/²) du
(25/2
L₁ (125/2.
4
° /* ( ²3 0²/²2 - 03/1²/²2 + 201¹/²) du
[₁₂ x²√x - 1 dx
(u5/2+2u³/2+u¹/2) du
Transcribed Image Text:Using the substitution u = expressed as an integral in terms of u is given by -1, the definite integral 5 2 2 ° 1² ( ² 0²² - ²3 0²²2 +4 201²/²) + 5/2 -u³/2 +2u¹/2 du 2 3 (5² +2³2 +0³/²) du (25/2 L₁ (125/2. 4 ° /* ( ²3 0²/²2 - 03/1²/²2 + 201¹/²) du [₁₂ x²√x - 1 dx (u5/2+2u³/2+u¹/2) du
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