Using the substitution 6 sin(u) = x, we obtain [²√36 - w²dx = [ K sin" u cos” udu where the constants K = m and n = Using this result and your knowledge about indefinite integrals of powers of sin u and cos u. find the indefinite in [x² √36- /36 = x²dx=+C Note: Your answer should be in terms of x, not u.

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Using the substitution 6 sin(u) = x, we obtain
[²√36 - x²dx = [ K sin" u cos" udu
where the constants K =
m
and n =
Using this result and your knowledge about indefinite integrals of powers of sin u and cos u. find the indefinite integral
| x² √/36 = x²dx = +0
Note: Your answer should be in terms of x, not u.
Transcribed Image Text:Using the substitution 6 sin(u) = x, we obtain [²√36 - x²dx = [ K sin" u cos" udu where the constants K = m and n = Using this result and your knowledge about indefinite integrals of powers of sin u and cos u. find the indefinite integral | x² √/36 = x²dx = +0 Note: Your answer should be in terms of x, not u.
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